8 5x+(4*(4+1)/2) =100
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LET THE BANANA EATEN ON FIRST DAY BE X-12
THEN ON FOLLOWING DAY MAN ATE X-6 , X ,x+6 , X+12
Then total banana eaten during five day is
x-12+x-6+x+x+6+x+12=100
=> 5x=100
=> x=20
so,banana eaten on first day is 20-12=8
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let,
he ate 'x' bnanas 1st day...then next four days he eats as following...
x+6, x+12, x+18 and x+24
hence, by summing all these we get,
x+x+6+x+12+x+18+x+24=100
=> 5x+60=100
=> 5x=40
=> x=40
hence, a man ate '6' bnanas on 1st day.
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Let the number of bananas he ate first day be x.
then x+x+6+x+12+x+18+x+24=100
=>5x+60=100
=>5x=40
x=8
that is, he ate 8 bananas on first day.
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You can use the formula to solve this problem.
5*a+5(5-1)6/2=100
a=8
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Let x be no of banans he ate on first day.
then on the next day he ate x+6,x+12,x+18,x+24
so x+x+6+x+12+x+18+x+24=100
so 5x+60=100
x=8
so he ate 8 banans on first day
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8 bananas
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Let, he ate 'x' bananas 1st day. then next four days he eats as following.
x+6, x+12, x+18 and x+24
hence, by summing all these we get,
x+x+6+x+12+x+18+x+24=100
=> 5x+60=100
=> 5x=40
=> x=8
Hence, a man ate '8' bananas on 1st day
All the best for your career
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x + (x+6) + (x+12) + (x+18) + (x+24) = 100
5x + 60 = 100
5x = 40
x = 8
ans is 8
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1st day = 08
2nd day (8+6) = 14
3rd day (14+6) = 20
4th day (20+6) = 26
5th day (26+6) = 32
Total = 100
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It can be considered as an arithmetic progression with first term a, common difference d=6, number of terms n=5, sum of first five terms=100.
n/2*(2a+(n-1)*d)=100;
5/2*(2a+4*6)=100;
a+12 =20;
a=20-12
= 8;
In the best rated answer there is a serious error; 5x =40; then how can x be 6;
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1st day 8 Bananas eaten, then
2nd day (8+6 more)= 14
3rd day (14+6 more)= 20
4th day (20+6 more)= 26
5th day (26+6 more)= 32
8+14+20+26+32 = 100 Bananas
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Answer is 8 bananas
Let suppose he eat x banana on first day, then
2nd day he eat x+6 banana
3rd day he eat x+12 banana
4th day he eat x+18 banana
and 5th day he eat x+24 banana
Hence from above
x+(x+6)+(x+12)+(x+18)+(x+24)=100
5x+60=100
5x=40
x=8
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As discussed earlier, there are two ways to find out the answers. We can use either
n*a+n(n-1)6/2= Given number ( here it is 100) or your can use AP method using x+(x+6)+..... However, 8 is the right answer.
Using First Method,
5*a+5(5-1)6/2=100
=>5a+5(4)*6/2=100
=>5a+20*6/2=100
=>5a=100-60
=>a=40/5=8
8 is the right answer
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Let the bananas ate I day be x
then no of banas eaten each are in AP and last term will be x+24
so applying formula for sum of terms of AP
Sn=100=5/2(x+(x+24))
x=8
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8 Bananas
6+12+18+24=60
100-60=40
40/5=8
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At the end it's
5x=40
So x=8
Correct it.
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5x+5/2(2*0+(5-1))*6=100
5x+60=100
x=(100-60)/5=8
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5 days, each day 6 bananas more than previous i.e
6 12 18 24 30
Sum comes out to be 90
i.e more ten bananas for 5 says...add 2 bananas for each day
ie
8 14 20 26 32
Therfore 1st day 8 bananas.
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Let, 'x' be the number of bananas he ate on 1st day, then next four days he eats as following.
x+6, x+12, x+18 and x+24
by summing all these we get,
x+x+6+x+12+x+18+x+24=100
=> 5x+60=100
=> 5x=40
=> x=8
The man ate '8' bnanas on 1st day.
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Let he eats x bananas on 1st day
2nd day x+6 and 3rd day x+6+6= x+12 bananas so it forms an arithmetic progression
Sum of this ap = 100
ie n/2(1st term + last term) = 100
n=5, 1st term = x, and last term = a+(n-1) d = x+ 4*6 = x+24 since d=6
ie 5/2(x+x+24) = 100
5(x+12) = 100
x+12 = 20
x = 8
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This forms an AP(arithmatic progression)
the summation of such a series is
S=(n/2)(2a+(n-1)d)
n-> no of terms, d->difference,a->initial term
substituting we get, S=100, n=5,d=6 so a=5
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Lets Say man ate X bananas on Day1 so
Day2 --> X+6
Day3 --> X+12
Day4 --> X+18
Day5 --> X+24
As we know he ate total 100 bananas in 5 days
so X+X+6+X+12+X+18+X+24 = 100
5X+60=100
5X=40
X=8
So he ate 8 Bananas on Day 1
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Let x be number bananas ate per day
then next day x+6
next day x+12,x+18,x+24
and its total equal to 100
i.e
x+x+6+x+12+x+18+x+24=100
5x+60=100
x=8
so 8 bananas per day
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Let the number of bananas a man ate on the first day be x,
then x,x+6,x+12......... is in arithmatic progression with commom difference 6.
so d=6 and n=5;
the sum of first n finite terms in AP is sn=(n/2)(2a+(n-1)d)
here sn=100
100=(5/2)(2a+4*6)
a=8
where a is the first term in AP
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Let x be the bannas he ate in 1st day. so,
x+x+6+x+12+x+18+x+24=100
5x+60=100
x=8.
so the bananas eaten by him in 1st day is 8.
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first day = "x" bananas
2nd day = x+6
3rd day = x+12
4th day = x+18
5th day = x+24
in five days he ate 100 bananas, so
x+x+6+x+12+x+18+x+24=100
5x+60=100
5x=100-60
5x= 40 therefore x = 8 bananas
proof: 8+14+20+26+32=100
hence prooved
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x + x+6 + x+12 + x+18 + x+24=100
5x + 60 = 100
5x=40
x=8
So Answer = 8 bananas
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day 1 = 8 bananas
day 2 =14
day 3 =20
day 4 =26
day 5 =32
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RAHUL CHANDAK
Answered On : Aug 14th, 2011
8
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KAPIL
Answered On : Aug 26th, 2011
On first day he will eat 8 bananas next day 14 then 20 then 26 and last day he will eat 32 bananas then the total will come
8+14+20+26+32=100
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rakend raj
Answered On : Aug 30th, 2011
8 bananas on the first day..
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U.MONICA DEVI
Answered On : Sep 10th, 2011
he had a chance to eat 76 bananas in first day coz he ate 100 bananas in 5 days n each day he increased his stuff by eating extra 6 day by day
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