let, he ate 'x' bnanas 1st day...then next four days he eats as following... x+6, x+12, x+18 and x+24 hence, by summing all these we get, x+x+6+x+12+x+18+x+24=100 => 5x+60=100 => 5x=40 => x=40 hence, a man ate '6' bnanas on 1st day.

Let x be no of banans he ate on first day. then on the next day he ate x+6,x+12,x+18,x+24 so x+x+6+x+12+x+18+x+24=100 so 5x+60=100 x=8 so he ate 8 banans on first day

Let, he ate 'x' bananas 1st day. then next four days he eats as following. x+6, x+12, x+18 and x+24 hence, by summing all these we get, x+x+6+x+12+x+18+x+24=100 => 5x+60=100 => 5x=40 => x=8 Hence, a man ate '8' bananas on 1st day

As discussed earlier, there are two ways to find out the answers. We can use either n*a+n(n-1)6/2= Given number ( here it is 100) or your can use AP method using x+(x+6)+..... However, 8 is the right answer.

Let the bananas ate I day be x then no of banas eaten each are in AP and last term will be x+24 so applying formula for sum of terms of AP Sn=100=5/2(x+(x+24)) x=8

5 days, each day 6 bananas more than previous i.e 6 12 18 24 30 Sum comes out to be 90 i.e more ten bananas for 5 says...add 2 bananas for each day ie 8 14 20 26 32 Therfore 1st day 8 bananas.

Let, 'x' be the number of bananas he ate on 1st day, then next four days he eats as following. x+6, x+12, x+18 and x+24 by summing all these we get, x+x+6+x+12+x+18+x+24=100 => 5x+60=100 => 5x=40 => x=8 The man ate '8' bnanas on 1st day.

Let he eats x bananas on 1st day 2nd day x+6 and 3rd day x+6+6= x+12 bananas so it forms an arithmetic progression

Sum of this ap = 100

ie n/2(1st term + last term) = 100 n=5, 1st term = x, and last term = a+(n-1) d = x+ 4*6 = x+24 since d=6 ie 5/2(x+x+24) = 100 5(x+12) = 100 x+12 = 20 x = 8

Let x be number bananas ate per day then next day x+6 next day x+12,x+18,x+24 and its total equal to 100 i.e x+x+6+x+12+x+18+x+24=100 5x+60=100 x=8 so 8 bananas per day

## 100 Bananas

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Let the number of bananas he ate first day be x.

then x+x+6+x+12+x+18+x+24=100

=>5x+60=100

=>5x=40

x=8

that is, he ate 8 bananas on first day.

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