C Interview Questions

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Answer is 3

In C language, int takes 2 bytes. Now 2 bytes mean 16 bits. One bit out of these 16 bits is for sign (+ or -) of integer. So, remaining 15 bits will store data in form of 0 and 1. The maximum value in...

C is not platform dependent because it does not generate the uniform executables.
suppose if we have build C code and generated binary in Windows and this same binary will not work on Linux.

It is true that *some* programs can be compiled on other systems without any changes and produce the same outputs. "Hello, World" should work everywhere with no changes. However, such trivially port...

Code
#include
#include
 
template T get_min_value(void)
{
    return (T) (1 << ((sizeof(T) << 3) - 1));
}
 
template T get_max_value(void)
{
    return (~(T) 0 - get_min_value());
}
 
template T get_umin_value(void)
{
    return (T) 0;
}
 
template T get_umax_value(void)
{
    return (~(T) 0);
}
 
int main()
{
    std::cout << "minmum signed integer - " << get_min_value() << std::endl;
    std::cout << "maxmum signed integer - " << get_max_value() << std::endl;
    std::cout << "minmum unsigned integer - " << get_umin_value() << std::endl;
    std::cout << "maxmum unsigned integer - " << get_umax_value() << std::endl;
 
    std::cout << "minmum signed short - " << get_min_value() << std::endl;
    std::cout << "maxmum signed short - " << get_max_value() << std::endl;
    std::cout << "minmum unsigned short - " << get_umin_value() << std::endl;
    std::cout << "maxmum unsigned short - " << get_umax_value() << std::endl;
}
 
 

first include limits.h
in that so many variables to find max and min value that can hold by any data type
for ex: INT_MAX,INT_MIN for integer and so on.......

Code
#include <iostream>
#include <fstream>
 
void display_sequence2(int depth)
{
    int output_count = 0;
    for (int count = depth - 1; count >= 0; --count) {
        for (int index = 0; index <= count; ++index)
            std::cout << (char) ((((output_count++ == 0) || (index == 2)) ? A : a) + index) << " ";
        for (int index = (count == (depth - 1)) ? count - 1 : count; index >= 0; --index) {
            std::cout << (char) ((((output_count++ == 0) || (index == 2)) ? A : a) + index);
            if (index > 0)
                std::cout << " ";
        }
    }
}
 
int main()
{
    display_sequence2(7);
}
 

Code
int i, j, k;
char a[] = { 'A', 'B', 'C', 'D', 'E', 'F', 'G' };
 
for (i = 0; i < 7; i++) {
    for (k = 0; k < 7 - i; k++)
        printf("%c ", a[k]);
    for (j = 7 - (i + 1); j >= 0; j--)
        printf("%c ", a[j]);
    printf("n");
}
 

Code
 
void reverse(char *str)
{
    int i = 0;
    for (i = 0; str[i] !=; i++) {
        printf("%c", str[i]);
        getch();
    }
 

Try this

Code
void reverse (int idx, char *str ) { 
     if (--idx < 0 ) { 
          return ; 
     } else { 
          putchar ( *(str + idx) ) ; 
          reverse (idx, str) ; 
     } 
}

"c void main() { char *chStrptr = "Hi This is Harish"; While(*ChStrPtr != /0) { LenOfStr++ chStrPtr++; } do { while(*chStrPtr != ) { chStrPtr--; LenOfStr...

I think you should use reverse string programme. You can store it an array and then run a loop.

Code
#include<stdio.h>
#include<conio.h>
main()
{
int i,a=0,b=1;
while(i<=9)
{
printf("%d ",a);
printf("%d ",b);
a=a+b;
b=b+a;
i++;
}
getch();
return 0;
}

Code
int main()
{
  int i=-1,j=1,sum=0,num;
  printf("ENTER THE LIMIT OF THE SERIES: ");
  scanf("%d",&num);
  while(sum<num)
    {
       sum=i+j;
       i=j;
       j=sum;
       printf("%d",sum);
    }
 getch();
}

mile

because it will skip starting 5 letters

Check this out:

Code
int a[3][3],b[3][3],c[3][3];
 
        int i,j,k;
        
        printf("enter the elements in A matrix:
");
        for(i=0;i<=2;i++)
        {
                for(j=0;j<=2;j++)
                {
                        scanf("%d",&a[i][j]);
                }
        }
 
        printf("enter b matrix:
");
        for(i=0;i<=2;i++)
        {
                for(j=0;j<=2;j++)
                {
                        scanf("%d",&b[i][j]);
                }
        }
 
        
        for(i=0;i<=2;i++) 
        {                    
        
                printf("
");
                for(j=0;j<=2;j++)
                {
        
                        c[i][j]=0;
                        for(k=0;k<=2;k++)
                        {
                                 c[i][j] = c[i][j]+a[i][k] * b[k][j];
                        }
                }
        }
        printf("multiplication matrix is:
");
        for(i=0;i<=2;i++)
        {
                for(j=0;j<=2;j++)
                {
                        printf("%d      ",c[i][j]);
                }
                printf("
");
        }

Code
 
main()
{
int a[10][10],b[10][10],c[10][10]:
int i,j,k;
printf("enter the elements in A matrix");
for(i=0;i<=5;i++)
    for(j=0;j<+5;j++)
{
scanf("%d",&a[i][j]);
}
printf("enter b matrix");
for(i=0;i<=5;i++)
    for(j=0;j<+5;j++)
{
scanf("%d",&b[i][j]);
 
 
}
c[0][0]=0;
for(i=0;i<=5;i++)
{                    [  this is main logic ]
for(j=0;j<=5;j++)
{
for(k=0;k<=5;k++)
{
c[i][j]=c[i][j]=c[k][j]+a[i][k]*b[k][j];
 
}
}
printf("multiplication matrix is");
for(i=0;i<=5;i++)
for(j=0;j<=5;j++)
printf("%d",c[i][j]):
} 
 

True, we should not be able to read a file after writing in that file without calling the given functions because if the file was open for writing and IF the last operation was an output operation, th...

A method is a subroutine to a class or it is a set of code referred by a name, these methods can be invoked or called at any part of the program to execute their set of codes.At runtime,methods have access to data stored in an instance of the class.A class can contain more than one methods.

Linker are used to convert the object code to executable codes where as linkage to a variable determines the deceleration of the variables declared in the given program.

Storage class are used to define the lifetime and scope of a function or available.There are four storage classes namely auto,static,register and extern storage classes. Storage variables are the vari...

There are seven stages of execution
1. Forming the goal
2. Forming the intention
3. Specifying an action
4. Executing the action
5. Perceiving the state of the world
6. Interpreting the state of the world
7. Evaluating the outcome

Indirection operator (denoted by *) is a unary operator which include pointer variables. It operates on a pointer variable,and returns a value equivalent to the value at the pointer address. Example:...

Malloc() and calloc() are used to allocate memory blocks dynamically.malloc() is a bit faster since it does not initialize the allocated memory blocks to as it is done by calloc() function.Hence it is better to use malloc() then calloc().

Code
int main(){
int a,b;
printf("Enter the two numbers: 
");
 
scanf("%d",&a);
scanf("%d",&b);
printf("Sum is: %d",add(a,b));
} 

Code
         #include<iostream.h>
         void main()
 {
      int i=20,j=30,m,n;
                         m=i,n=j;
if(i<j)
{
          for(i=1;i<=m;i++)
                        j++;
         cout<<j;
}
else
{
        for(j=1;j<=n;j++)
                 i++;
  cout<<i;
}
 }

end of file is a function which returns zero value at end of file... EOF is a deliminator

End of Line refers to the 'n'( new line character). It will perform operations till it come across 'n'.

EOF refers to End of File. It is the last character in the file.(if it is not empty). If the file is empty then only EOF will be present.
Some compilers give its value as -1.

"c void rmdup(int *array, int length) { int *current, *end = array + length - 1; for (current = array + 1; array < end; array++, current = array + 1) { while (current < ...