by hit n trial method orange cost will b rs 2 for 1 orange

banana rs 1 for 1

apple rs 2 for 1 apple

so d cost of 3 orange ,3 banana ,3 apple =rs 15

RAJESH KUMAR BEHERA

Feb 16th, 2015

15

hanumanth

Apr 21st, 2015

2x+3y+4z=15
3x+2y+z=10
x=2,y=1,z=2
3x+3y+3z=15

Mounika

Jul 17th, 2017

2 oranges + 3 bananas + 4 apple=15RS
3 oranges + 2 bananas + 1 apple=10RS
so now
5 oranges+ 5 bananas + 5 apples = 25RS
so
5( 1 orange +1 banana + 1 apple)=5(5)
5 gets cancelled
so since they asked 3 oranges + 3 bananas + 3 apples =3(1 orange + 1 banana + 1 apple) = 3(5)
= 15

Ashok Rawat

Nov 4th, 2017

Hi
I think
I can be 15 bcz
2x+3y+4z=15
3x+2y+1z=10
So adding
5x+5y+5z=25
Let 5 LCM
5(x+y+z)=25
x+y+z=5
So 1 orange, 1 banana, 1 apple is cost 5 Rs.
Then 3 orange, 3 banana, 3 apple costs 15 Rs.
its solved. Ans= 15

## 2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges, 2 bananas, and 1 apple costs Rs 10. What is the cost of 3 oranges, 3 bananas and 3 apples?

This question is related to TCS Interview## Editorial / Best Answer

Answered by: devendra

hi,

i think

it can be 15 bcoz

2x+3y+4z=15

3x+2y+z=10

adding

5x+5y+5z=25

x+y+z=5 that is for 1 orange ,1 bannana and 1 apple requires 5Rs.

so for 3 orange ,3 bannana and 3 apple requires 15Rs.

i.e. 3x+3y+3z=15........

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