A man ate 100 bananas in five days, each day eating 6 more than the previous day. How many bananas did he eat on the first day?

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kuntal sarkar  

  • Member Since Feb-2008 | Feb 9th, 2008


x+(x+6)+(x+12)+(x+18)+(x+24)=100
or, x=8

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mbhatia

  • May 4th, 2008
 

he ate 8 bananas on the first day. its simple mathematical logic...which we have been taught in SAT or every other entrance exams.

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x= banana on first day
 for five corresponding days
x+x+6+x+12+x+18+x+24=100
5x+60=100
5x=40
x=8
first day=8
second day=x+6=8+6=14
third day=20
fourth day=26
fifth day=32

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mnbvcxz

  • Sep 9th, 2008
 

let the banana eaten by him on the first day be x. each day  he is eating 6 more than the first day. so x+(x+6)+(x+12)+(x+18)+(x+24)=100. solving this we get x=8. there fore the number of banana eaten by him on the first day is 8.

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let he eat (x-12) banana on first day
then he will eat (x-6,x,x+6,x+12) on next four days
then according to condition;
                                                 x-12+x-6+x+x+6+x+12=100
                                                    5x=100
                                                     x=20
number of banana that he ate on first =20-12
                                                             =8



                                                                                       ANSWER=8

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Answer is 8 as
Consider the no of bananas he ate on day 1 as X;
Then no of bananas on day2 - X+6
On day3 - X+6+6=X+12
On day 4 - X+18
& on day 5 - X+24
So the equation becomes
X+(X+6)+(X+12)+(X+18)+(X+24)=100
5X+60=100
5X=100-60=40
x=40/5=8.

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meenakshi gupta

  • Nov 27th, 2015
 

let the person eat x-12,x-6,x,x+6,x+12 in 5 days
then 5x=100
x=20
so first day will be 20-12 ie 8 ans.

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Imdadul

  • Dec 10th, 2015
 

10

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shaik.chand

  • Dec 17th, 2015
 

x+(x+6)+(x+12)+(x+18)+(x+24)=100
5x+60=100
5x=100-60
x=40/5
x=8.
so he ate daily 8 bananas

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as

  • Jun 21st, 2016
 

8

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Pintal

  • Jul 12th, 2016
 

8

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priti

  • Jul 14th, 2016
 

100/5=20
avg of all term in AP middle term so,
1.2.3.4.5 the middle term=1+5/2=3 on third day he ate 20 bananas,
so 1 2 3 4 5
8 14 20 26 30
so on 1st day he ate 8 bananas

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vinod raj

  • Jul 26th, 2016
 

On the first day he would have eaten 76 bananas
2nd day= 82 (76+6 more then the previous day)
3rd day = 88 (82 + 6 more than previous day)
4th day = (88 +6) 5th day (94 +6 == 100 reached)

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Dharmishtha

  • Jul 28th, 2016
 

x+(x+6)+(x+12)+(x+18)+(x+24)=100
so now
6+12+18+24=60
then 100-60=40
40/5=8
so on the first day he eat 8 bananas
and so 8, 14,20,26,32=100

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suresh

  • Jul 30th, 2016
 

Ans: Eight

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RD

  • Aug 20th, 2017
 

x + (x+6) + (x+12) + (x+18) + (x+24) =100
5x + 36+24 = 100
5x = 40
x = 8

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Prabhu Murugan

  • Dec 4th, 2017
 

40. first day = 40 second day = 46, third day = 58, fourthday = 76 fifth day = 100

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hitzbab

  • Apr 24th, 2018
 

x=8+(8+6)+(14+6)+(20+6)+(26+6)=100

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