C FAQs

Semicolon

A. Semicolon

Answer to the question 10"c /* * Write a C program to find a two digit number, the second digit of which is * smaller than its first digit by 4, and if the number was divided by ...

Answer to the question 1"c /* C program to find a peculiar two digit number which is three times the sum * of its digits. * Solution :- * let say number is 10x+y * According ...

error: #include expects "FILENAME" or
error: expected identifier or { before } token

#include

void main()
{
int a=1;
if(a=1,3,5,6)
printf("good&a=%d",a);
else
printf("bad&a=%d",a);

}

//Output

good&a=1

good&a=1

use the structure to write this program

/*Write a C program using arrays and any loop statements that asks the user to enter the number of students. For each student, enter the number of courses. The user should enter the students ID number...

Since the pointers point to a memory location issues of dangling pointers and wild pointers can occur. Dangling pointers are those pointers when the data at which they are pointed may have been modifi...

D. Any where in the program.

Any where in the program

It allocate 2bytes in memory

2 byte for tc & 4 byte for gcc compiler

Memory allocated is in some other format

1336

Code
#include<stdio.h> 
#include<conio.h>
void main() 
{
int i,j,k=0;
for(i=3;i<=3333;i++)
{
        j=i%10;
        if(j==3)
        {
                k=k+1;
        }
}
printf("times %d
",k);
}

Code
int main()
{
        int n,m,i,j;
        scanf("%d",&n);
        for(i=1;i<=n;i++)
          { for(j=1;j<=n-i;j++)
               printf(" ");
          for(j=i;j>=1;j--)
              printf("%d        ",j);
           for(j=2;j<=i;j++)
              printf("%d        ",j);
          printf("
");
          }
        return 0;
}

The size of pointer variable depends on the processor architecture that is 32-bit or 64-bit.It may vary according to compiler we are used.

The size of a pointer variable is 2 bytes which is the size of unsigned integer as pointer variables are always used to store addresses.

Multiple values can be returned from a function by using call by address i.e. pointers intelligently.

Strictly speaking, a C function can only *return* a single value; you cant write something like "a,b,c=f();". However, you can write to multiple function parameters in addition to returning a value (...

The answer is 84

The second digit 4 is smaller than the first digit by 4
sum of the digits is 12
84/12=7

malloc is the memory allocation operator whereas calloc is the memory release operator

malloc: malloc create the single block of given size by user calloc: calloc creates multiple blocks of given size both return void pointer(void *)so boh requires type casting malloc: eg: int *p; p=(...

Code
#include<stdio.h> 
#include<conio.h>
void main() 
{
int i=54,j=43;
printf("BEFORE SWAPPPED
");
printf("%d,%d
",i,j);
i=i+j;
j=i-j;
i=i-j;
printf("BEFORE SWAPPPED
");
printf("%d,%d
",i,j);
}

#include
void main()
{
int a,b,temp;
printf("Enter values for a and b ");
scanf("%d %d",&a , &b);
printf("values before swaping are : %d %d",a,b);
temp=a;
a=b;
b=temp;
printf("After swaping values are : a= %d b=%d,a,b);
getch();
}

Which operation in the following expression will be performed first?

c = a++ / b + 5;

c = a++ + ++a + ++a Compiler starts from leftmost operand

Code
1+5 = 6
 
a = 6 
 
1+6 =7
 
a = 6+7
 
a =13
 
1+13 =14
 
Now
 
c = 6+ ++7 ++13
 
c = 28

Per the C language standard, there must be *at least* 127 levels of nesting.

There is no such limitations you can use any no of nested if statement.

The general idea is that short "always" represents a 16-bit integer, whereas int represents whatever the native word size is for that particular architecture (16- or 32-bit). "Always" is in scare quo...

Sorry to say that actually in most of C compiler short int is also of 16 bit and they are equivalent to each other.