shashi

• May 23rd, 2005

 

the share is increased by M/(M-3) of $D.

suresh

• May 31st, 2005

 

D$

prashanth n

• Jun 3rd, 2005

 

40.28 % for each of his original amount they want to spend for party

shweta

• Jul 14th, 2005

 

3D(/m-3)

nmodi

• Jul 17th, 2005

 

3D/(m-3) is correct

abhishek

• Sep 28th, 2005

 

ANS=$6D/(M-3)

amitkr_12

 Profile Answers by amitkr_12 

• Dec 9th, 2005

 

3D/(m*(m-3)

pugal

• Jul 30th, 2006

 

hai,

 can u give the method u get it. 

how do i use this thread?

• Oct 27th, 2006

 

3D/(M(M-3))

Sung

• Oct 28th, 2006

 

To get the Total amount for each person would be like this

   D/(M-3)

    for example => D =70 M=10

                         normally each person would get (D/M) $7

                         but after there  are 3 less persons it would be (D/(M-3)

                          Then it would come to $10 per person

  another example D= 200 M=5

                         Normally each person would get (D/M) $40 per person

                         but after ther are 3 less persons (D/(M-3) $100 per person 

                           

vishwa828

 Profile Answers by vishwa828 

• Dec 7th, 2006

 

if M persons are there and $D is there share! then the total is MDnow the no of persons would be M-3 and their share increasesso now there share would be (MD/(M-3))so increase would beMD(/(M-3))-D=(3D)/(M-3)

jigar4601

 Profile Answers by jigar4601 

• Feb 25th, 2009

 

3D/M-3 is the correct answer only...

Nahfees

 Profile Answers by Nahfees 

• Mar 23rd, 2009

 

Let D = X / M , where is the an amount of money  => (1 )

D1 = (D + Y) , y is the increase in share

D1 = X / ( M -3 ) , since there 3 person less but same amount of money (2)

from equation (1) and (2)

DM = D1 (M-3)
D1 = DM/(M-3)

Replace D1 by (D + y)

D + y  = DM/(M-3)
y =   DM/(M-3) - D
y =  D( (M-(M-3))/(M-3))
y = D(3/(M-3)

Thus y = 3D/(M-3)
Which is the increase in amount

nag_rajk

 Profile Answers by nag_rajk 

• Mar 24th, 2009

 

If the no. of persons are M, and the spent is $D, then the amount spent by each of them is 

             $D/M   =   $X   ----------- (1)


 If 3 persons were absent then the amount spent by each of the member is


            $D/(M-3) =  $Y   --- -------- (2)

  Now (2)-(1) gives the answer i.e.the increased share to be paid by each individual

 If M be 5 persons and dD be $100, then accordingly X=20 and Y=50 so the increased share is $30.

hydsarema

 Profile Answers by hydsarema 

• May 21st, 2009

 

The share of each person is $D
Since the total number of persons are M the total amount is  $(M*D)

Since 3 persons were reduced the number of persons become M-3
(M-3)*share isequal to $DM
so share is equal to $DM/(M-3)
the increase in share is ($DM/M-3)-$D

chaitu038

 Profile Answers by chaitu038 

• Sep 24th, 2009

 

MD = x
(M-3)D1 = x

==> MD = (M-3)D1
==> D1 = MD/(M-3)

Ans = MD/(M-3)

mrprajesh

 Profile Answers by mrprajesh 

• Dec 21st, 2009

 

3D/(m-3) is the new share value okay.
But the question is "how much share will be increased for each individual."

Actual share is D, so increase by (3D/(m-3)) - D

shankarbala

 Profile Answers by shankarbala 

• Dec 31st, 2009

 

Total for the party is $D
M persons included in this so share of 1 person is given by $D/M
and now the 3 persons are absent
so now total amount of persons is M-3
and the total amount for party remain the same as $D
and now the new share for each person will be $D/(M-3)
so the increase in their share will be $D/(M-3)  - $D/M
This will give 3$D/(M*(M-3))

raviaspirant

 Profile Answers by raviaspirant 

• Sep 4th, 2010

 

Given no of persons =m

each share = D

 Then total expenditure = D*M

Now the same expenditure sahred by 3 persons less = (D*M)/(M-3)

Difference =  DM/(M-3)  -  D  = 3D/(M-3)

Subhankar_smit

 Profile Answers by Subhankar_smit 

• Jun 5th, 2011

 

The increased share of each individual will be = ((M*$D)/(M-3)) - ($D)

seth

• Nov 3rd, 2011

 

total amount of fee is M*D

3people absent, fee for each is M*D/(M-3)

It asks how much increased, so M*D/(M-3)-D

nidhi agrawal

• Aug 13th, 2012

 

(3*D/((M-3)*M))