shashi

• May 23rd, 2005

 

pie/2r percent

nmodi

• Jul 17th, 2005

 

225% for circle and 337.5% for shpere

irfan

• Jul 19th, 2005

 

increase in volume for sphere is 237.5% 

simon

 Profile Answers by simon 

• Sep 22nd, 2005

 

2*50+50*50/100  = 125%ans

spher== 1.5*1.5*1.5-1  = 2.375

% increase = 2.375/1*100 =237.5

srilakshmi

• Dec 30th, 2005

 

ans is 237.5%

kalyantheprince

 Profile Answers by kalyantheprince 

• Jan 5th, 2006

 

volume of sphere initially = 4/3*(pi) r^3

since radius is increased by 50%

so new radius =  1.5r

so new volume of sphere = 4/3*(pi)*(1.5r)^3

                                  =3.375*4/3*(pi)*r^3

                                  =4/3*(pi) r^3 + 2.375*4/3*(pi)*r^3

So total increase in volume of sphere = 237.5%

swati

• Mar 31st, 2006

 

ans is 67.5

bob

• Sep 12th, 2006

 

if a cube increases 50% in length, how much does the volume change?

hari2912

 Profile Answers by hari2912 

• Oct 26th, 2009

 

Let initial radius = R
New Radius = R + 50R/100 = 3R/2
Volume of a sphere = 4 * pi * r^3
new volume for new radius = 4 * pi * (3R/2)^3
= 4*pi*27R/8
therefore, volume has increased by 27/8 times
in percentage: (27/8)*100
= 337.5%

Gayathri B

• Nov 17th, 2014

 

last step i didnt understd., how we ett 237.5% from the preivious step????????????

Arijit

• Feb 15th, 2017

 

Let the radius be x
A/q, new radius =x + 50%of x
=X+50/100^x x
=3x/2
Vol. of Sphere = 88x³/21
Vol. of Sphere with new radius=99x³/7
difference in volumes= 99x³/7-88x³/21
=209x³/21
Increase in volume = 209x³/21/88x³/21 ×100
= 209/88×100
= 237.42