Aptitude - Jalia is twice older than Qurban

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Jalia is twice older than Qurban

Jalia is twice older than qurban. If jalia was 4 years younger, Qurban was 3 years older their difference between their ages is 12 years. What is the sum of their ages?
a)67
b)57
c)36
d)none

Total Answers and Comments: 6

Last Update: March 05, 2009 Asked by: chandradeepika

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Best Rated Answer

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Submitted by: Raze2dust

Let Qurban's age be x.
jalia's age=2x
It is given that
had jalia been 4 years youger and qurban 3 yaers older the difference of thier ages would have been 12 years.
If we make an equation, 2x - 4-(x+3)=12
i.e 2x-4-x-3=12
i.e x-7=12
x=12+7=19 years
Qurban's age=19 years
Jalia's age=19*2
=38 years
Sum of ages =19+38=57 years

Above answer was rated as good by the following members:
ajkush, chandu.jntu, smokincigar07

June 16, 2008 14:00:35

write4srini

Member Since: February 2008 Contribution: 1

RE: Jalia is twice older than Qurban

b.57

dono eact method but solved from options...

first check C option...
divide 36 into 3 parts since give that J 2Q...

hence 36/3
12
if q 12 thn j 24

but if (j-4)-(q+3) 12
ths condition is not satisfied...

now take 57...

divide 57/3

19

hence j 38 & q 19

now check condition (j-4)-(q+3) 12

hence the answer is

B.) 57

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June 23, 2008 04:14:34

sreenath91

Member Since: June 2008 Contribution: 5

RE: Jalia is twice older than Qurban

very simple logic is take julia as 2x
qurban as x

then]
(2x-4)-(x+3) 12
so x 19
so the present sum of ages is 38+19 57

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November 08, 2008 09:41:02

Raze2dust

Member Since: November 2008 Contribution: 3

RE: Jalia is twice older than Qurban

Let Qurban's age be x.
jalia's age 2x
It is given that
had jalia been 4 years youger and qurban 3 yaers older the difference of thier ages would have been 12 years.
If we make an equation 2x - 4-(x+3) 12
i.e 2x-4-x-3 12
i.e x-7 12
x 12+7 19 years
Qurban's age 19 years
Jalia's age 19*2
38 years
Sum of ages 19+38 57 years

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February 02, 2009 06:28:30

purvamehta

Member Since: February 2009 Contribution: 1

RE: Jalia is twice older than Qurban

Jalia's age is 2x
Qurban's is x

(2x-4)-(x+3) 12
x 19

Therefore sum of their ages is 57.

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March 01, 2009 14:41:30

amirth1

Member Since: March 2009 Contribution: 1

RE: Jalia is twice older than Qurban

Let j be Jalia'S age and q be Qurban's age.
eq 1 > j 2Q
eq 2 > (J-4)-(Q+3) 12
> J-Q 19

Sub eq 1 in 2
> 2q-q 19 ie. Q-19.

sub q 19 in 1
j 38

J+Q 57

Ans (b) 57

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March 05, 2009 07:58:52

madhurimasridhar

Member Since: March 2009 Contribution: 8

RE: Jalia is twice older than Qurban

Suppose Qurban is x yrs. then Jaila is 2x yrs (twice older than Qurban)

If Jaila is 4 yrs younger Qurban is 3 yrs older then their ages diff is 12 yrs

so (2x-4)- (x+3) 12
Now we solve it we got x value as 19yrs

So sum of their ages is 38+19 57.

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