-
File transfer Question
A file is transferred from one location to another in ,buckets,. The size of the bucket is 10 kilobytes. The bucket gets filled at the rate of 0.0001 kilobytes per millisecond. The transmission time from sender to receiver is 10 milliseconds per bucket. After the receipt of the bucket the receiver sends an acknowledgement that reaches sender in 100 milliseconds. Assuming no error during transmission,...
smokincigar07
- Feb 20th, 2010
The speed at which a bucket filled is is 0.0001 kilobytes per millisecondi.e 0.1 kilobytes per secondfor Nkb time is 10N secondsNo. of buckets k=N/10 where k is the higher intiger(i.e if N/10=2.2 then...
prasadude
- Dec 13th, 2008
the speed at which a bucket filled is is 0.0001 kilobytes per millisecondthis is re-written as 0.1 kilobytes per secondi.e 100 seconds to fill a bucket which is 10kb in sizetransmission time is 10 mil...
-
Power cable question
A power cable is to be run from a power plant on the bank of a river 900 meters wide to a factory that is located 3000 meters downstream on the opposite bank. If the cost of laying cable under water is Rs. 5 per meter and that of laying overhead on land is Rs. 4 per meter, find the point downstream where the cable is to cut across the river.
smokincigar07
- Feb 20th, 2010
<(3000-x)->C A------------------------------------------------------ ^ | ...
agkjack
- Nov 17th, 2009
I do not think it is complex. They give cost to plant the cable in ground and water both also
Let assume the length across the river is x;By given cost 5x=4*3000+5*900so x=3300 3300/2=1650so the point is 1650m from x axis, and 450m(half of distance bet banks) from y axis(450,1650) -
Jalia is twice older than Qurban
Jalia is twice older than qurban. If jalia was 4 years younger, Qurban was 3 years older their difference between their ages is 12 years. What is the sum of their ages?a)67 b)57 c)36 d)none
prititripathi
- Dec 20th, 2010
Let qurban age x n julia =2x so acc. to que2x-4-(x+3)=12x=19 n julia age= 38 sum of their age =19+38=57
madhurimasridhar
- Mar 5th, 2009
Suppose Qurban is x yrs. then Jaila is 2x yrs (twice older than Qurban)If Jaila is 4 yrs younger, Qurban is 3 yrs older then their ages diff is 12 yrsso (2x-4)- (x+3) = 12Now we solve it we got x value as 19yrsSo sum of their ages is 38+19 = 57.
