RE: What are the steps for handling concurrent request...
I believe it can be done by creating the XMLHTTPRequest object from within an inner function, instead of creating a seperate function for making a new XmlHttprequest object withing the same page...
RE: What are the steps for handling concurrent requests in AJAX?
In order to handle the request concurrently, its always better to achive through writing the separate function. For e.g.
xmlHTTPObj.Onreadystatechange = function1();
The above line of code will help us to do asynchronous processing. So function1() will be called when the XMLHTTP request object goes to on ready state change.
Dont forget to set the parameter "TRUE" in the Open method of xmlHTTPObj. The followign e.g. shows this.
"true" reperesents the processing carried after the send() method, without waiting for a response. "false" means that processing waits for the response before continuing.
RE: What are the steps for handling concurrent requests in AJAX?
AJAX - Asynchronous Java Script AND XML. Using AJAX your Java script can directly communicate with server.
AJAX use XMLHttpRequest Object to communicate with Server..
Now It Works..
XMLHttpRequest Object have three Different Properties.
1) OnReadyStateChangePropert - After Request to Server You need a Function to store the Response from Server.
xmlHttp.onreadystatechange = function (){
}
2) ReadyState = Using This Propert you can Check the Response State.
ReadyState = 0 It Means Request Initialized ReadyState = 1 It Means Request set up ReadyState = 2 It Means Request sent ReadyState = 3 It Means Request Progress ReadyState = 4 It Means Request Complete
3) ResponseText = Data Sent By Server will get By Response Text Property.
Steps... 1) First Check The xmlHttp Request Object Which Supports your Browser
Internet explorer -- ActiveXObject FireFox -- XmlHttpRequest Object
2) Then Use These Property
xmlHttp.onReadyStateChange = function () {
if (xmlHttp.ReadyState == 4) { document.getelementByid.innerHtml('center') = xmlHttp.ResponseText; }
}
3)xmlHttp.open("GET","Name of Page , you are requesting",true); 4)xmlHttp.send(null);
RE: What are the steps for handling concurrent requests in AJAX?
3) xmlHttp.open("GET","Name of Page , you are requesting",true);
Can anyone explain how can I use POST method for sending data to Servlet? I want to send an object which contains all the data directly to servlet instead of GET
