Aptitude - A person from washington came to india.One evening at 6.00 p m he started walking at the speed

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A person from washington came to india.
One evening at 6.00 p m he started walking at the speed of 40 km/hr and
climbed the slope at speed of 30 km/hr.
From there he walked back to the source at the same speed at 9.00 p m.
what is the distance he covered in one way.

12 kms

Total Answers and Comments: 9

Last Update: July 06, 2009

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October 04, 2005 13:05:03

premsagar

Member Since: October 2005 Contribution: 4

RE: A person from washington came to india.One ...

answer is wrong. even he walks at 30km/hr for 3 hours we will cover 90km.

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January 07, 2006 12:52:50

arati_nayak2000

Member Since: December 2005 Contribution: 5

RE: A person from washington came to india.One ...

52.5 km

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March 31, 2006 12:40:49

Poornima

RE: A person from washington came to india.One ...

Could u plz tell me how u got the distance as 52.5km.

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April 10, 2006 14:46:17

Ravindra

RE: A person from washington came to india.One ...

average speed (40+30)/2 35;
so the total distance x+y 35*(3/2) 52.5

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May 11, 2006 17:56:15

harry

RE: A person from washington came to india.One ...

Ans:105kmread the question carefully...he starts his return journey at 9:00pm..so one way journey time is 3hrsso the eqn becomesavg spd 35kmph(x+y)/35 3 >x+y 35*3 105...

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September 18, 2007 01:24:05

keerthi

RE: A person from washington came to india.One ...

I did not understand why you are saying his one way is 3hrs
I could solve in this way
t1 time taken on level road. t2 uphill. t3 down hill;

the distance traveled uphill and down hill same so

t2*30 30*t3; > t2 t3;---> (1)

total time 2*t1 + t2 + t3 3 hours ---> (2)

2t1+2t3 3 -->(3)

total distance 2*(40t1) + 30*t2+30*t3 ---> (4)

substitute (1) in (4)

80t1 + 60t3 > 40(2t1+3t3) then from (3)

here 2t1 3-2t3 --->(3)
so
40(3-2t3+3t3)
40(3+t3)
But here I am not able to solve

Can you help me

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November 04, 2007 04:54:31

kat

RE: A person from washington came to india.One ...

avg speed should be calculated by (x*y)/(x+Y) (40*30)/70 17.14
therefore 17.14 * 3

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June 25, 2008 23:04:22

sravan_reddy001

Member Since: November 2005 Contribution: 8

RE: A person from washington came to india.One evening at 6.00 p m he started walking at the speed of 40 km/hr andclimbed the slope at speed of 30 km/hr.From there he walked back to the source at the same speed at 9.00 p m.what is the distance he co

x -> distance on ground
y -> distance on slope

speed on upslope and downslope is same(given) 30
speed on level ground is 40(given)

time taken : 2(x/40+y/30) 3

> 4x+3y 180
by trial and error --> x 30 y 20

2(x+y) -> 100 kms

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July 03, 2009 05:27:27

Reshu.v

Member Since: June 2009 Contribution: 1

Total distance 100km.
While going starting speed is 40km/hr he walks for 60min i.e. distance 40km

While climbing speed is 30km/hr he walks for 20min i.e. distance 10km
While cumin back speed is 30km/hr he walks for 100min i.e. distance 50km

Total time 60+20+100 180min 3hrs(given)
Total speed 40+10+50 100km.

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