What distance he covered in one way?

A man walks at 4 km/hr on plain, then at 3 km/hr uphill and then returns through the same road at 6 km/hr downhill and at 4 km/hr on the plain. It takes altogether 6 hours. So what distance he covered in one way?

Questions by yash.yashu29

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Naveen Kg

  • May 13th, 2011
 

total distance 2 reach up d top and return back =24km!!!

let us consider flat land=x km and slope land=y km

speed @ flat land=4kmph,==> 4km=1hr=>1km=1/4hr
thus, for x km==>x/4hr

speed a@ walkin up @ slope=3kmph==>3km=1hr==>1km=1/3 hr
thus for ykm==y/3hr

speed returning back in slope=6kmph==>6km=1hr==>1km=1/6hr
thus for ykm==y/6hr

thus total hour for travel=x/4 +y/3 +y/6 +x/4 =6 hours
solving , x+y=12km

thus total distance to go to top of hill and return back =12+12=24km :)

deog123

  • May 18th, 2011
 

So what distance he covered in one way?

We need to consider only distance in one direction. i.e. (x+y)

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uling728

  • Jul 3rd, 2011
 

24.

t_p: the time for plain. t_up: the time for uphill. t_down:: the time for downhill.

(1):  t_up * 3 = t_down * 6 ==> t_up = 2 * t_down ; because they have the same distance.
(2): t_p + t_up + t_down + t_p = 6;  total time 6.
(3): (1) + (2) ==> 2*t_p + 3*t_down = 6;

(4) total distance = 2* 4 * t_p + 3* t_up + 6*t_down
                            = 8*t_p + 12 * t_down
                             = 4 *(2*t_p + 3*t_down)
                             = 4 * 6 
                              =  24

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