Series: Subject: Topic:
Question: 17 of 222

Cache Memory Access Time

A hierarical catche memory subsystem has a catche access time of 50ns and the main storage access time is of 500ns . If 80% of memory request are for the read and th ehot ratio of 0.9, what is the average access time of the system considering only memory read cycle in the write through scheme?
Asked by: saurabhupd | Member Since Apr-2010 | Asked on: Apr 19th, 2010

View all questions by saurabhupd

Showing Answers 1 - 1 of 1 Answers

Answered On : Aug 27th, 2010

View all answers by swarna_coolguy

Average access time for memory read=hit ratio*cache access time+(1-hit ratio)*main memory access timeTherefore , Avg access time = 0.9 * 50ns + ( 1- 0.9 ) * 500ns = 95 ns

Login to rate this answer.

Give your answer:

If you think the above answer is not correct, Please select a reason and add your answer below.

Related Open Questions



twitter fb Linkedin GPlus RSS


Question Categories

Shell Scripting Interview Questions

Solaris Admin Interview Questions

UNIX Interview Questions

Unix Programming Interview Questions

Windows Interview Questions

Interview Question

 Ask Interview Question?


Latest Questions

Interview & Career Tips

Get invaluable Interview and Career Tips delivered directly to your inbox. Get your news alert set up today, Once you confirm your Email subscription, you will be able to download Job Inteview Questions Ebook . Please contact me if you there is any issue with the download.