A hierarical catche memory subsystem has a catche access time of 50ns and the main storage access time is of 500ns . If 80% of memory request are for the read and th ehot ratio of 0.9, what is the average access time of the system considering only memory read cycle in the write through scheme?

Salihu

• Aug 28th, 2018

The access time of a cache memory is 120 ns and that of main memory 900 ns. It is estimated that 80% of the memory requests are for read and remaining 20% for write. The hit ratio for read access only...

swarna_coolguy

 Profile Answers by swarna_coolguy Questions by swarna_coolguy

• Aug 27th, 2010

Average access time for memory read=hit ratio*cache access time+(1-hit ratio)*main memory access timeTherefore , Avg access time = 0.9 * 50ns + ( 1- 0.9 ) * 500ns = 95 ns

Answer Question  Select Best Answer