Once there came many birds to a pond. There were certain number of lotus flowers in the pond. If each bird occupied one lotus one bird was left alone without any flower. If two birds sat in a flower one flower was left behind. Find the total number of birds and flowers.

There are 4 birds and 3 lotus flowers. When each bird sit on 1 lotus flower, one bird will be left without a flower. When two birds sit on 1 lotus flower, then one flower will be left out.

If one bird occupy 1 flower then one left. If there are n no. of bird and m no. of flowers Then relation among them n=m+1 In 2nd case m=n/2+1 by solving we get n=4 and m=3

Since, when one bird each sits on one flower, one bird is left out, the difference between number of birds(b) and number of flowers(f) is 1. ie.. b-f=1 When 2 birds sit on one flower, one flower is left out, so 2(f-1)=b...

b-f=1... 1st equation 2(f-1)=b... 2nd equation

Solving these tw equations we get, b=4, f=3

So, the number of birs are 4 and number of flowers are 3

Let us consider the number of flowers is x and that the number of birds is y

Now as per the question when 1 bird tried to occupy 1 flower each, 1 bird is left behind which means that the number of birds is 1 more than the number of flowers

=> y=x+1---------------1

also when 2 birds tried to acquire 1 flower each then 1 flower is left extra

Let no. of birds is "b" and no. of lotus be "l" Now, a/c to first condition--> b = l+1 & a/c to snd condition--> b/2 = l-1 Solving above equations, we get, No. of Bird=4 & No. of Lotus = 3

## Once there came many birds to a pond

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Ans:=4 birds & 3 flowers

If 1 bird sat on one lotus 1 bird left behind & if 2 bird sit on 1 lotus then 1 lotus left behind.

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