hydsarema

 Profile Answers by hydsarema 

• Nov 25th, 2008

 

derived function is called
to demonstrate  this is the foll program


#include<iostream.h>
#include<conio.h>

class base
  {
     public: virtual void vfun()
      {
        cout<<"this is base virtual function calling";
      }
  };

  class derived1:public base
     {
       public:void vfun()
       {
  cout<<"this is derived function calling";
       }
     };

     void main()
     {
       clrscr();

       base *p,b;//base class pointer is created

       derived1 ob1;

       p=&ob1;//initialise base class pointer with derived class

       p->vfun();//derived function is called

       getch();
     }
    /* output
     this is derived function calling*/

PUSHPANKAR

 Profile Answers by PUSHPANKAR 

• Mar 22nd, 2010

 

The base pointer is pointing towards the derived object therefore the derived object will be called