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A car is traveling at a uniform speed. The driver sees a milestone showing a 2-digit number. After traveling for an hour the
driver sees another milestone with the same digits in reverse order. After another hour the driver sees another milestone containing
the same two digits with a zero in between(0). What is the average speed of the driver.

PLEASE EXPLAIN STEP WISE

  
Total Answers and Comments: 2 Last Update: June 20, 2008     Asked by: shrutim 
  
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 Best Rated Answer
Submitted by: swamidayalsrivastava
 

Let 10'splace digit is x and unit's place digit y

First milestone :      10x+y
Second milestone : 10y+x
Third milestone:      100x+y

Since the speed is uniform so
  Distance covered in first Hr = Distance covered in Second Hr
  (10y+x)-(10x+y) = (100x+y)-(10y+x)
After solving, we get  ---->   y=6x  but since x and y are digits so only possible combination is x=1 and y=6,
  So average speed = 45 KM/HR



Above answer was rated as good by the following members:
rahulr30, SpandanaMohan, robinmnit, jayagopal, balasmart75
September 26, 2007 04:59:48   #1  
swamidayalsrivastava        

RE: A car is traveling at a uniform speed. The driver ...

Let 10'splace digit is x and unit's place digit y

First milestone : 10x+y
Second milestone : 10y+x
Third milestone: 100x+y

Since the speed is uniform so
Distance covered in first Hr Distance covered in Second Hr
(10y+x)-(10x+y) (100x+y)-(10y+x)
After solving we get ----> y 6x but since x and y are digits so only possible combination is x 1 and y 6
So average speed 45 KM/HR


 
Is this answer useful? Yes | NoAnswer is useful 5   Answer is not useful 0Overall Rating: +5    
June 20, 2008 12:58:18   #2  
varun.pulyani Member Since: June 2008   Contribution: 2    

RE: A car is traveling at a uniform speed. The driver sees a milestone showing a 2-digit number. After traveling for an hour thedriver sees another milestone with the same digits in reverse order. After another hour the driver sees another milestone conta

Without using equations :-

1st distance xy
2nd distance yx
3rd x0y or y0x
since first 2 valuess r two digits....avg speed can't be greater than 100.
Thus difference between 2nd and 3rd value is also less than 100.
Thus third distance is in 100's
thus x 1
now checking for possibility of y y 6
Average speed 45


 
Is this answer useful? Yes | NoAnswer is useful 1   Answer is not useful 0Overall Rating: +1    

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