P.Senthilkumar

• Aug 2nd, 2007

 

Consider x is Son & y is Father.
 
   ie, x=y/2 and x=1/3(y-10)

So, Father's age  is 20.
   

esha

• Aug 24th, 2007

 

let the fathers age be f and son's age be s
s=.5f => f=2s..................1
(f-10)/3=(s-10) => f-10=3s-30
3s-f=20.............................2
solving 1 and 2
we get son's age as 20 and fathers age as 40

puspanjali

• Aug 27th, 2007

 

let father's age is:- y
and son's age is :-x
  
  present age son =>x=y/2
   before 10 year the age of son is=>x=y/3

        so now y/2=y/3+10
          
   by solving this we get y=60

     so presently the age of the father is  60 and age of the son is 30
      where the age of the son was before 10 year is 1/3rd of the age of his father that is 20 year.

jayakrishnan

• Sep 25th, 2007

 

I accept the answer of Puspanjali

let father's age is:- F
and son's age is :- S
   
  present age son =>S=F/2
   before 10 year the age of son is=>S-10=F/3

        Substituing S=F/2 in S-10=F/3          

F/2-10=F/3
cross multiplying this we get,
(F-20)=2F/3
3F-60=2F
Now
3F-2F=60
Therefore F=60

     so presently the age of the father is  60 and age of the son is 30
      where the age of the son was before 10 year is 1/3rd of the age of his father that is 20 year.

rahman_cam

 Profile Answers by rahman_cam 

• Dec 23rd, 2007

 

let Fathers Present age is = X;
Son's Present age is = X/2;

10 years back......


Son's age= (X/2)-10-----------1


According to Given Statement:

Son's age=(1/3)(X-10)-------------2

on Equating 1 and 2 we get


(1/3)(X-10) = (X/2)-10

which gives X=40..... (Which is Father's Present Age...)

steph47

 Profile Answers by steph47 

• Feb 14th, 2008

 

lets sons age be S and fathers age be F

TODAY SONS AGE IS HALF OF FATHERS AGE

  WE HAVE  S= 1/2 F

10 YEARS AGO IT WAS 1/3RD OF FATHERS AGE

S-10 =1/3(F-10)

SUBSTITUTING ,F =2S IN THE ABOVE EQN WE GET

S AS 20

THATS IS THE SONS PRESENT AGE AND THEREFORE FATHERS PRESENT AGE WILL BE 2S  I.E  2*20 = 40 YR

FATHERS PRESENT AGE IS 40

mayur_moradiya

 Profile Answers by mayur_moradiya 

• Apr 18th, 2008

 

suppose, x is son, so that father is 2x
       10 years back son is x-10 and father is 2x-10

       which is 1/3 of the father sons that's wy

            x-10=(2x-10)*(1/3)
           x=20 , so father is 2x=40

sinju

 Profile Answers by sinju 

• May 25th, 2008

 

let son's age b'x' n father's age b'y'.
given s "x= y/2"


but 10 yrs back ,
                          (x-10)=(1/3)*(y-10)
                          so,,,y=40
                           now that s after 10 yrs father's age ll b "+10"
                         therefore, y+10 = 50

praneet143

 Profile Answers by praneet143 

• Jun 19th, 2008

 

Father

praneet143

 Profile Answers by praneet143 

• Jun 19th, 2008

 

fathers's age is 60

vivekbhc

 Profile Answers by vivekbhc Questions by vivekbhc

• Jul 21st, 2008

 

let the age of father is x;
the age of the sone=x/2;
ten yrs back, the age of father is x-10;
                      the age of son is    x/2-10;
              at the same time son=1/3(x-10)
         so x/2-10=1/3(x-10)
       solving we get x=40 and x/2=20
       hence the age of father is 40 and the age of the son is 20;

vivekbhc

 Profile Answers by vivekbhc Questions by vivekbhc

• Jul 21st, 2008

 

the age of father is x;
the age of son is x/2;
10 yrs back
age of fater is x-10;
age of son is x/2-10;
at the same time age of son is 1/3(x-10)
x/2-10=1/3(x-10), solving we get x=40 and x/2=20
so the age of father is 40 and the age of son is 20;

saiduth

 Profile Answers by saiduth 

• Aug 17th, 2008

 

Let the father's present age be    'x'
so that son's age is                      'x/2'
and ten years back  father's age  'x-10'
ten years back sons age               '(x/2)-10'
so that according to the given condition  1/3(x-10)=(x/2)-10.............(1)
solving equation we get x=40 that is father's present age is 40
and sons age is 'x/2' that is 20

deepak643

 Profile Answers by deepak643 

• Jan 5th, 2009

 

Yes sure it is 40 ie., The age of the father
Consider if 40 is the fathers age sure 20 is the age of the son if it is half so 1st condition is satisfied and go ten years back so dads age is 30 and sons age is 10, it is satisfying the 2nd condition i.e, 1/3rd of the fathers age so fathers age is 40 and sons age is 20.

madhurimasridhar

 Profile Answers by madhurimasridhar 

• Mar 6th, 2009

 

Suppose father's age is x yrs.
Then son's age is x/2 yrs.
After 10 yrs.
Back son's age is x/2-10 that is equal to 1/3rd age of father (x/3).
x/2-10 = x/3
We solve it and get value of x as 60. which was father's age 60yrs.
His present age is 60yrs.

logosubramanian

 Profile Answers by logosubramanian 

• Jun 19th, 2009

 

Let my age be=x
Therefore my son's age=x/2=1/3 * (x-10)+10

x/2=x/3-10/3+10
10-10/3=x/2-x/3
20/3=x/6
x=40



ans:40

siva_ponsha

 Profile Answers by siva_ponsha 

• Aug 27th, 2009

 

My present age is 40 and my son is 20
Before 10 years my age is 30 and my son is 10

Sakshi Beri

 Profile Answers by Sakshi Beri 

• Nov 24th, 2010

 

Let son's age be x years

and father's age be y years

x=1/2y .................(1)

10 years back

son age=x-10 years

father age=y-10 years

x-10=1/3(y-10) ......(2)

Solving (1) and (2)  we get

x=20 i.e, son's age

y=40 i.e, father's age

bshnayar

 Profile Answers by bshnayar 

• Dec 31st, 2010

 

Let present age of father be x yrs
Hence present age of son is x/2
10 yrs back fathers age is (x-10)yrs
and sons age was 1/3(x-10)
Hence 1/3(x-10)+10=x/2
x=40
Present age of father is 40 yrs