This program works fine only for a number containing three digits.

But i prefer to intake these three digits at the time of scanning as a string rather than a single number for the flexibility of the program.

#include<string.h>
#include<stdio.h>

main()
{
char string_of_integers[4];
char first 0;
char second 0;
char third 0;

printf("nGive any three digit number");
scanf("n s" string_of_integers);

printf("nThe required combinations are:n")

for(first 0;first< 2;first++)
for(second 0;second< 2;second++)
for(third 0;third< 2;third++)
printf(" c c ct" string_of_integers[first] string_of_integers[second] string_of_integers[third]);

printf("nThis is the end of the program");
getch();

}

Expand the logic to make it work for more number of digits and also use some additional verificational logic if you are to work with varying number of digits i mean you need to add extra logic if at all flexibility needs to be a attribute of the program.

/*to print possible patern using given no*/
#include<stdio.h>
#include<conio.h>
void main()
{
int a[100] b[100] n x 1 y k j i m c;
clrscr();
printf("enter no of nost");
scanf(" d" &n);
m n-1;
printf("nenter nost");
for(i 0 c m;i<n;i++ c--)
{
printf("n");
scanf(" d" &a[i]);
b[c] a[i];
}
for(i 1;i< n;i++)
{ x x*i; }
printf(" dnnn" x);

y x/2;
for(i 0;i<x;i++)
{
if(i<y)
{
for(j 0;j<n;j++)
{
if(j 0)
a[n] a[0];
k j+1;
a[j] a[k];
printf(" d " a[j]);
}

}
else
{

for(j 0;j<n;j++)
{
if(j 0)
b[n] b[0];
k j+1;
b[j] b[k];
printf(" d " b[j]);
}
}
printf("nn");
}
getch();
}