let the fathers age be f and son's age be s s=.5f => f=2s..................1 (f-10)/3=(s-10) => f-10=3s-30 3s-f=20.............................2 solving 1 and 2 we get son's age as 20 and fathers age as 40
RE: My son is half of my age & was 1/3rd of my age 10 ...
let the fathers age be f and son's age be s s .5f > f 2s..................1 (f-10)/3 (s-10) > f-10 3s-30 3s-f 20.............................2 solving 1 and 2 we get son's age as 20 and fathers age as 40
RE: My son is half of my age & was 1/3rd of my age 10 ...
let father's age is:- y and son's age is :-x
present age son >x y/2 before 10 year the age of son is >x y/3
so now y/2 y/3+10
by solving this we get y 60
so presently the age of the father is 60 and age of the son is 30 where the age of the son was before 10 year is 1/3rd of the age of his father that is 20 year.
RE: My son is half of my age & was 1/3rd of my age 10 ...
I accept the answer of Puspanjali
let father's age is:- F and son's age is :- S
present age son >S F/2 before 10 year the age of son is >S-10 F/3
Substituing S F/2 in S-10 F/3
F/2-10 F/3 cross multiplying this we get (F-20) 2F/3 3F-60 2F Now 3F-2F 60 Therefore F 60
so presently the age of the father is 60 and age of the son is 30 where the age of the son was before 10 year is 1/3rd of the age of his father that is 20 year.