If the digits of my present age are reversed then i get the age of my son.If 1 year ago my age was twice as that of my son.Find my present age

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Jun 14th, 2007
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i_upal

Profile Answers by i_upal Questions by i_upal

Member Since Apr-2007 | Sep 23rd, 2007

My age : 10x+y
Son age : 10y+x

so 10x+y = 10y+x
     10x+y-1 = 2(10y+x-1)
     x = (19y-1)/8

for y=3
           (19y-1) is completely divisible by 8
so x = 7

So my present age : 10*7+3 = 73
             son's age  :  10*3+7 = 37

Showing Answers 1 - 12 of 12 Answers

i_upal
Profile Answers by i_upal

Sep 23rd, 2007

My age : 10x+y
Son age : 10y+x

so 10x+y = 10y+x
     10x+y-1 = 2(10y+x-1)
     x = (19y-1)/8

for y=3
           (19y-1) is completely divisible by 8
so x = 7

So my present age : 10*7+3 = 73
             son's age  :  10*3+7 = 37

naveenkumar17
Profile Answers by naveenkumar17

Feb 19th, 2009

My age : 10x+y
Son age : 10y+x
So 10x+y = 10y+x
10x+y-1 = 2(10y+x-1)
x = (19y-1)/8
For y=3 (19y-1) is completely divisible by 8
So x = 7
So my present age : 10*7+3 = 73
Son's age : 10*3+7 = 37

veeru21
Profile Answers by veeru21

Feb 19th, 2009

73 if we reverse it is 37
one year ago 36*2 = 72

milan.kadivar
Profile Answers by milan.kadivar

Feb 20th, 2009

My age : 10x+y
Son age : 10y+x

so 10x+y = 10y+x
     10x+y-1 = 2(10y+x-1)
     x = (19y-1)/8

for y=3
           (19y-1) is divisible by 8

Therefore x = 7

So my present age : 10*7+3 = 73
             son's age  :  10*3+7 = 37