In a pasture, the grass grows at an even rate. 40 cows can completely eat the grass in 40 days, if there are 30 cows the grass last fot 60 days, for how long it is sufficient for 20 cows 1) 80 2)90 3)100 4)120 5 )none

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Suganya

  • Dec 2nd, 2006
 

Ans: 80Reason:The days will be increased by 20 as the number of cows decreases by 10

Sunny

  • Dec 15th, 2006
 

Ans is 90
reason is as the no. of cows is reduced by 10 the grass is increased by exactly adding half of the previous grass i.e., when 40 cows 40 grass, then 30 cows 60 grass, Similarly 20 cows 90 (60+30) grass.

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manoj

  • Dec 31st, 2006
 

100 reson: x*(40/30)=20x=15then multiplay x with 40/60 ratio100

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Prakash Kumar

  • Mar 20th, 2007
 


hi

40 cow can complately eat the grass in 40 days it means there is 40 * 40 = 1600 cow are able to eat the food

for 20 cow = 1600/20 = 80 Days Ans

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Sagar

  • Apr 1st, 2007
 

the answer is 120..  this is the correct answer

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shyaamsundar

  • Apr 11th, 2008
 

Let I be the initial Grass
      g br the rate of growth of grass per day
      r be the rate of consumption of grass by one cow in one day

For 40 cows
       I+40g=40*40r   -------------------------1
for 30 cows
       I+60g=30*60r   --------------------------2
Then for 20 cows
       I+ng=20*n*r      -------------------------3
                   where n is the no of days

Subtracting the first two equation and dividing it by 20
        g=10r
Subtracting the equations 2 and 3 and  subustituting the value of g 

we get 
      n=120       

Giriraj Gupta

  • Sep 4th, 2015
 

What about: 30 cows eat the grass in thirty days. so 30*60=1800
for 20 cows: 1800/20=90.
so this approach cant be apply.
Incorrect logic . right..?

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harsh kumar

  • Sep 5th, 2015
 

90

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MAHESH BHATNAGAR

  • Sep 16th, 2015
 

90

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Haseeb`

  • Sep 19th, 2015
 

80

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Mohan Singh

  • Sep 24th, 2015
 

1) 80

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deepa

  • Sep 28th, 2015
 

4) 120

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