How to solve questions which involves arthematic operations on alphabets like xxxx yyyy +zzzz====== yxxxz======

This question is related to Dell Interview

Interview Candidate
May 11th, 2006
10
16776

Showing Answers 1 - 10 of 10 Answers

buzz

May 14th, 2006

x=9y=1z=8

vaibhav chauhan

May 24th, 2006

   i dont know how u solv that but here is my approach
           x x x x
           y y y y
           + z z z z
---------------------------------
           y x x x z
---------------------------------
so we can say that
z = z from zero's place
     x = x+y+z; for ten's place so x from both LHS and RHS get cancel and we will get y = -z;
same for hunderads and thousand place
for Ten Thousand place we get y = x+y; i.e. x = 0;
so we get x = 0; y = -z;

Samriti Jindal

Jun 12th, 2006

x=9y=1z=8x=8z=8/19y=x9y=8y=8/9z=9yz=9*8/9z=8/1proved for correctness.

naveen

Jul 13th, 2006

Absolutely fantastic
Your analysis is superb.

SRINIVAS_SRIT

Jul 18th, 2007

R4 R3 R2 R1
x x x x
y y y y
+ z z z z
---------------------------------
y x x x z
A4 A3 A2 A1
--------------------------------
FIRST EQ: FROM ROW R1
X+Y+Z=10+Z ------>(1)
FROM ROW R2:
X+Y+Z+1= X+10;
THEN Y+Z=9------->(2)
FROM ROW R3:
SAME AS ABOVE R2 Y+Z=-1;
FROM ROW R4:
HERE Y VALUE IS 1.
SUM OF X,Y,Z IS LESS THEN 20 WHY BECAUSE X,Y,Z VALUES ARE BELOW TEN AND NOT REPEATABLE.
*X+Y+Z<20 MEANS 20=10 SO WE CAN GET Y VALUE FROM
ROW R4 : Y IS THE CARRY OF (X+Y+Z+1) THIS IS LESS THEN 20 GREATER
THAN 10 SO WE CAN TAKE Y=1;
SUBSTITUTE Y VALUE IN EQ (1): X+Y+Z=Z+10;
1+X=10;
THEN
X=9;
THEN SUBSTITUTE Y VALUE IN EQ(2):
Y+Z=9:
1+Z=9;
THEN Z=8:
RESULT IS:X=9,Y=1,Z=8.