i dont know how u solv that but here is my approach
x x x x
y y y y
+ z z z z
---------------------------------
y x x x z
---------------------------------
so we can say that
z = z from zero's place
x = x+y+z; for ten's place so x from both LHS and RHS get cancel and we will get y = -z;
same for hunderads and thousand place
for Ten Thousand place we get y = x+y; i.e. x = 0;
so we get x = 0; y = -z;
Samriti Jindal
Jun 12th, 2006
x=9y=1z=8x=8z=8/19y=x9y=8y=8/9z=9yz=9*8/9z=8/1proved for correctness.
naveen
Jul 13th, 2006
Absolutely fantastic
Your analysis is superb.
SRINIVAS_SRIT
Jul 18th, 2007
R4 R3 R2 R1 x x x x y y y y + z z z z --------------------------------- y x x x z A4 A3 A2 A1 -------------------------------- FIRST EQ: FROM ROW R1 X+Y+Z=10+Z ------>(1) FROM ROW R2: X+Y+Z+1= X+10; THEN Y+Z=9------->(2) FROM ROW R3: SAME AS ABOVE R2 Y+Z=-1; FROM ROW R4: HERE Y VALUE IS 1. SUM OF X,Y,Z IS LESS THEN 20 WHY BECAUSE X,Y,Z VALUES ARE BELOW TEN AND NOT REPEATABLE. *X+Y+Z<20 MEANS 20=10 SO WE CAN GET Y VALUE FROM ROW R4 : Y IS THE CARRY OF (X+Y+Z+1) THIS IS LESS THEN 20 GREATER THAN 10 SO WE CAN TAKE Y=1; SUBSTITUTE Y VALUE IN EQ (1): X+Y+Z=Z+10; 1+X=10; THEN X=9; THEN SUBSTITUTE Y VALUE IN EQ(2): Y+Z=9: 1+Z=9; THEN Z=8: RESULT IS:X=9,Y=1,Z=8.
How to solve questions which involves arthematic operations on alphabets like xxxx yyyy +zzzz====== yxxxz======
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