Hi friendz, This sequence is from ibm paper... Can u plz give solution and expln.. 1. 7,6,8,5,3,7,? 2. 13 9,18,21,25,20,? 3. 3,3,4,8,10,36,? 4. 15,30,28,25,20,34,28,? Thnq in advance...
Sequence Pattern: 3 3 4 8 10 36 ?Solution: Odd Sequence Starting from First : 3 4 10 ? Even Sequence Starting from Second : 3 8 36 Calculating Odd Sequence: (3 * 1) + 1 = 3 (4 * 2) + 2 = 10 (10*3) + 3 = 33 Ans Note: Multiplication is happening with consecutive numbers and so is the addition. Calculating Even Sequence: (3*2) + 2 = 8 (8*4) + 4 = 10 (10*6) + 6 = 66 Note: Multiplication is happening with even numbers and so is the addition.Hence the final sequence would be 3 3 4 8 10 36 33 (Ans) 66
hai freinds the continuation of the first sequence is 4 as the series will continue as 768537417 as the second term 6 and ist term is 6+1=7 and 3rd term is 7+1=8 and 5th term is 6-3=3 thus the sequence will continue as 417... and the consequtive 3rd term is 7 ok bye to allÂ
3 ,3,4,8,10,36,... there are 2 sequences, both start from 3.. the sequence 3,4,10....has the first number 3 next 3*1+1=4 4*2 +2=10 10*3+ 3=33 now... he sequence at even places 3*2 +2=8 8*4 +4=10 10*6 +6 =66 so the numbers are 3,3,4,8,10,36,33,66
the digit count of the sequence isof the form..... (ie)1+5=6 3+0=3 2+8=1 etc. 6 3 1 7 2 7 1 .....so the remaining two nos. should have the count 3 and 6 respectively..... moreover the flow of the sequence is "the second no. is greater than first and all other are less upto the no. with count 2(i.e) middle no.
and the no. next to middle no. (i.e)34 is greater than 20... so all others should be less than 34....
on keeping all these in mind... v ll have 21 : 2+1=3 15 : 1+5=6
