What is the product of the irrational roots of the equation (2x-1)(2x-3)(2x-5)(2x-7)=9?

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hussain

  • Apr 4th, 2006
 

ans : x = 2

(2x-1)*(2x-3)*(2x-5)*(2x-7) = 9

(2*2-1)*(2*2-3)*(2*2-5)*(2*2-7) = 9

divya

  • Oct 3rd, 2006
 

ya the answer is 2.

if its 3/2..c the value becomes 0 on the LHS.

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Ans: 1.5

Explanation: The equation have four roots, are 2, 2, 3.5811, .41881
after some simplyfication we get (x-2)^2*(2x^2-8x+3)=0; means (2x^2-8x+3)=0; comparing quadratic equation ax^2+bx+c=0; The product of roots is c/a yeilds 3/2=1.5.
Thanks

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divi

  • Sep 18th, 2011
 

there the answer is product of irrational roots only not all the roots..so answer is 3/2 only

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vijayan

  • Feb 27th, 2012
 

For this question we should realize the answer through answer only...we should substitute the options then finally we can recognize the correct answer...if we substitute 3/2 instead of x,we will get zero...by substituting other answers we can't...then the answer is 3/2

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akshatha hebbar

  • Sep 12th, 2014
 

Product of irrational roots...
X= ((1/2)*(4+√10))*((1/2)*4-√10)
X=3/2

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Naveen

  • Sep 28th, 2014
 

This is a fourth degree equation. Therefore it will have 4 roots (real or imaginary). It clearly has 2 equal roots equal to 2. Constant term = (-1)*(-3)*(-5)*(-7) -9 = 96. Coefficient of x^4 = 2*2*2*2 = 16
Hence product of other 2 roots = 96/(16*2*2) = 3/2 = 1.5

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SHUBHAM KARANJKAR

  • Sep 13th, 2017
 

-3x-1x1x3=9
So x=3

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Balloo

  • Oct 30th, 2018
 

8

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Bhawna

  • Jun 23rd, 2020
 

How could you find out that there are 2 equal roots=2

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