The Question is wrong
if R+B+G=20
and G = 7
so R+B+7=20
R+B=13

So R+B < 13 does not hold good

AussieMike

Sep 10th, 2014

I agree with Vin
Total Balls = T = 20
G = 7
R+B < 13
so that means G+R+B < T, so there must be a fourth color X to make T=R+G+B+X = 20
X+(R+B) = 13
max(R+B) = 12
If we make the assumption that there must be at least one blue ball, at most there can be 11 red balls.
If we make the assumption that there don't have to be any blue balls, at most there can be 12 red balls.

sathya narayanan.R

Oct 28th, 2014

6

Don Pryor

Nov 12th, 2014

6

Umer

Nov 16th, 2014

I dont think Question is complete. As If max number of red balls is 6 then there must be a condition that red and blue balls are equal of less n grater something.

sangeeta

Nov 17th, 2014

6

ridwan

Nov 28th, 2014

7. as the question asked at most how many balls are red and the highest answer is 7 so...

Parashuram

Dec 19th, 2014

6

dav

Dec 19th, 2014

7

Kunal

Apr 26th, 2015

11 coz sum of red and blue balls are less than 13 i.e. 12.....hence, there could be a possibility of having 11 red balls and 1 blue ball

## Probability

A. 4

B. 5

C. 6

D. 7

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