# Price of Cow

A man sold two cows for Rs. 210 at a total profit of 5 %. He sold one cow at a loss of 10% and another at a profit of 10%. What is the price of each cow?
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#### Priyanka_Bansal Profile Answers by Priyanka_Bansal

• Aug 28th, 2010

99 Rs each. Total 198

#### Nasim2 Profile Answers by Nasim2

• Sep 1st, 2010

5% profit

so, if selling price =105  cost price=100
or, if selling price=210 cost price=200

now total profit=210-200=10
Let,two cows of cost price x and 200-x

So, -x/10+(200-x)/10=10

or, x = 50
one cow cost price=Rs. 50
another cow=200-50=150

#### Pradeep Narra Profile Answers by Pradeep Narra

• Sep 3rd, 2010

x1*1.1 + X2*0.9 = 210; // with profits
x1 + X2 = 200; // removing the profit we get the original sum

solving both....
x1 = 150;
x2 = 50;

#### S.P.K.A. Profile Answers by S.P.K.A.

• Sep 28th, 2010

The cost of 2 cows is 200.
Overall Profit is 10 Rs..

The cost of 1st cow (sold for 10% loss) is 50 Rs. i.e. loss=5 Rs
The cost of 2nd cow (sold for 10% profit) is 150Rs. i.e. profit=15 Rs.

#### khushbu.kathiriya Profile Answers by khushbu.kathiriya

• Oct 27th, 2010

Total 5% profit on Rs.210 i.e. Original Price=200Rs.

Suppose one cow is of  X Rs.
i.e. another is of 200-X Rs.

now loss of 10% on X  =10x/100
& profit of 10% on (200-x) =(200-x)10/100

i.e.
x-[10x/100]+[200-x]+[(200-x)10/100]=210

By Solving this x=50

so one cow is of x=50Rs.
& Other is of 200-x = 200-50 = 150Rs.  