Sum of 1....100=(100(101))/2 [formula n(n+1)/2] The no '6' occurs at 10 times in 1st place from 1....100 so 10*3=30 [6 is incremented by 3] At 10th place, no '6' occurs 10 times from 1....100 so 10*30=300 sum=5050+300+30 =5380

n=100, sum of nos=n(n+1)/2 i.e.. 100(100+1)/2=5050. Single 6 occurs 9 times from 1 to 100 and 9-6=3. So 9*3=27. Double 6 occurs 1 time, 99-66=33. So the new sum is 5050+27+33=5110.

Sum of 1 to 100 is 5050. Number 6 is repeted 10 times between 1 to 100 so (3*10=30) Now add the 30 to actual answer (5050+30=5080). Therefore the answer is 5080

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