# Sum of Numbers

If all 6 are replaced by 9 then sum of all the numbers from 1 to 100 is?

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#### mutha_macks Profile Answers by mutha_macks Questions by mutha_macks

• Aug 22nd, 2008

Ans: 5380

#### madhavimca Profile Answers by madhavimca

• Oct 11th, 2008

Sum of 1....100=(100(101))/2 [formula n(n+1)/2]
The no '6' occurs at 10 times in 1st place from 1....100
so 10*3=30 [6 is incremented by 3]
At 10th place, no '6' occurs 10 times from 1....100
so 10*30=300
sum=5050+300+30 =5380

Ans:5380

#### vivek.rick Profile Answers by vivek.rick

• Nov 30th, 2009

n=100, sum of nos=n(n+1)/2
i.e.. 100(100+1)/2=5050.
Single 6 occurs 9 times from 1 to 100 and 9-6=3.
So 9*3=27.
Double 6 occurs 1 time, 99-66=33.
So the new sum is 5050+27+33=5110.

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#### m_manic Profile Answers by m_manic Questions by m_manic

• Dec 9th, 2009

The sum is 5377

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#### m_manic Profile Answers by m_manic Questions by m_manic

• Dec 9th, 2009

Sum for 1 to 100 is 5050.

5050 - (16+26+36+46+56+60+61+62+63+64+65+66+67+68+69+76+86+96) + (19+29+39+49+59+90+91+92+93+94+95+96+97+98+99+79+89+99) = 5377

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#### m_manic Profile Answers by m_manic Questions by m_manic

• Dec 10th, 2009

Sorry, In my previous posting I missed one number. I will correct it now

Sum for 1 to 100 is 5050.

5050 - (6+16+26+36+46+56+60+61+62+63+64+65+66+67+68+69+76+86+96) + (9+19+29+39+49+59+90+91+92+93+94+95+96+97+98+99+79+89+99) = 5380

#### arunkumar_sona Profile Answers by arunkumar_sona

• Dec 11th, 2009

Sum for 1 to 100 is 5050.

5050 - (6+16+26+36+46+56+60+61+62+63+64+65+66+67+68+69+76+86+96) + (9+19+29+39+49+59+90+91+92+93+94+95+99+97+98+99+79+89+99) =5380

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#### mitvenkatesan Profile Answers by mitvenkatesan

• Dec 11th, 2009

Sum of natural number is n(n+1)/2
Totaly 6's on one's position =10 (ie. 3*10=30)
Totaly 6's on ten's position =10 (ie  30*10=300)
Sum=5050+30+300=5380.

#### krishna127 Profile Answers by krishna127

• Apr 1st, 2010

Sum of 1 to 100 is 5050. Number 6 is repeted 10 times between 1 to 100
so (3*10=30)
Now add the 30 to actual answer
(5050+30=5080).
Therefore the answer is 5080

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#### chirutha48 Profile Answers by chirutha48

• May 29th, 2010

6 in tens digits are also replaced by 9's. so +30
6 in units place replaced by 9's so +3
therfore sum of 1 to 100 5050
5050+3*10+30*10=5380

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#### abdul.rehman Profile Answers by abdul.rehman

• Sep 23rd, 2010

The answer is 330 i.e 5380-5050=330

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#### shankarleelap Profile Answers by shankarleelap

• Jan 29th, 2011

9-6=3

and every change in 9 with 3 will get a diffenrence of 3
=>   there will be 10 no's with 3 in units place whose place value is 1
=>     there will be increase in sum by (3*1)*10=30
=>   and also there will be 10 no's with 3 in tens place whose place value is 10
=>    there will be increase in sum by (3*10)*10=300
=>   total increase will be 300+30=330
there fore the sum will be 1+2+3+.......+100+330=  5050+330=?

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#### SAIKIRAN

• Sep 17th, 2011

1416

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