C - Sum of two numbers without using arithmetic operators

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C | Question 424 of 453

Sum of two numbers without using arithmetic operators

ex:
int a=10;
int b=10;
int sum=a+b;
without using "+" operator calculate sum

Total Answers and Comments: 11

Last Update: July 18, 2009 Asked by: meda_reddy

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Best Rated Answer

—

Submitted by: jintojos

void main()
{
          int a=10,b=20;
          while(b--) a++;
           printf("Sum is :%d",a);
}

Above answer was rated as good by the following members:
ranganath_yadav, PAVAN86, Jaya_Kaja, rajani_vaddepalli15, pachaimuthu84

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July 17, 2008 06:41:48

jintojos

Member Since: May 2008 Contribution: 29

RE: sum of two numbers without using arithmetic operators

void main()
{
int a 10 b 20;
while(b--) a++;
printf("Sum is : d" a);
}

Is this answer useful? Yes | No

5 0

Overall Rating: +5

July 17, 2008 12:44:10

veeranarayana

Member Since: July 2008 Contribution: 1

RE: sum of two numbers without using arithmetic operators

int i j;
if(i<j)
{
for(i 0;i< j;i++)
j++;
cout<<j;
}
else
{
for(j 0;j< i;j++)
i++;
cout<<i;
}

Is this answer useful? Yes | No

1 0

Overall Rating: +1

July 18, 2008 12:22:08

ceren6

Member Since: July 2008 Contribution: 2

RE: sum of two numbers without using arithmetic operators

#include <stdio.h>

int main ()

{

unsigned int t 0xffffffff;

unsigned int z 1;

int a 10 b 10 sum 0 r 0;

while (t) {

int t1 t2;

t1 a & 0x00000001;

t2 b & 0x00000001;

if ((t1 ^ t2 ^ r) 1) {

if (t1 1 && t2 1 && r 1)

r 1;

else

r 0;

sum sum | z;

} else {

if (t1 0 && t2 0 && r 0)

r 0;

else

r 1;

}

a >> 1;

b >> 1;

z << 1;

t >> 1;

}

printf ("sum: dn" sum);

return 0;

}

Is this answer useful? Yes | No

July 21, 2008 05:48:29

ceren6

Member Since: July 2008 Contribution: 2

RE: sum of two numbers without using arithmetic operators

Operator Name	Syntax	Overloadable	Included in C
Arithmetic operators
Unary Plus	+a	Yes	Yes
Addition (Sum)	a + b	Yes	Yes
Prefix Increment	++a	Yes	Yes
Postfix Increment	a++	Yes	Yes
Assignment by Addition	a + b	Yes	Yes
Unary Minus (Negation)	-a	Yes	Yes
Subtraction (Difference)	a - b	Yes	Yes
Prefix Decrement	--a	Yes	Yes
Postfix Decrement	a--	Yes	Yes
Assignment by Subtraction	a - b	Yes	Yes
Multiplication (Product)	a * b	Yes	Yes
Assignment by Multiplication	a * b	Yes	Yes
Division (Quotient)	a / b	Yes	Yes
Assignment by Division	a / b	Yes	Yes
Modulus (Remainder)	a b	Yes	Yes
Assignment by Modulus	a b	Yes	Yes

Is this answer useful? Yes | No

1 0

Overall Rating: +1

August 14, 2008 13:18:18

Saurabh Sharma

Member Since: August 2008 Contribution: 1

RE: sum of two numbers without using arithmetic operators

Use minus operator :-
int a 10 b 20 c;
c a-(-b);

Is this answer useful? Yes | No

August 22, 2008 01:50:32

sriranga.ch

Member Since: August 2008 Contribution: 5

RE: sum of two numbers without using arithmetic operators

void main()
{
int a 10 b 10;
a a<<1;
b b<<1;
printf("Sum of a&b is dn" (a&b));
}

Is this answer useful? Yes | No

August 25, 2008 00:36:04

shiva chitta

Member Since: August 2008 Contribution: 2

RE: sum of two numbers without using arithmetic operators

#include add(int a int b)
{
if(!a) return b;
else return add((a&b)<<1 a^b);
}
void main()
{ int a 2 b 5 c; c add(a b);
cout<<c;
}

hope it 'll help you right...........

Is this answer useful? Yes | No

September 09, 2008 15:45:00

rashmi.mohanty

Member Since: September 2008 Contribution: 8

RE: sum of two numbers without using arithmetic operators

void main(){
int a 5 b 7 i;
for(i 1;i< a;i++)
b++;
printf("sum value: d" b);
}

Is this answer useful? Yes | No

November 02, 2008 13:51:52

npatwardhan

Member Since: November 2008 Contribution: 1

RE: sum of two numbers without using arithmetic operators

for(i 0; i < a ;i++)
{

count++;
}
for(j 0;j< b;j++)
{
count++;
}

printf( d count);