C - sum of two numbers without using arithmetic operators

GeekInterview.com > Interview Questions > Programming > C

Go To First | Previous Question | Next Question

C | Question 424 of 437

sum of two numbers without using arithmetic operators

ex:
int a=10;
int b=10;
int sum=a+b;
without using "+" operator calculate sum

Total Answers and Comments: 8

Last Update: September 09, 2008 Asked by: meda_reddy

Sponsored Links

Best Rated Answer

—

Submitted by: jintojos

void main()
{
          int a=10,b=20;
          while(b--) a++;
           printf("Sum is :%d",a);
}

Above answer was rated as good by the following members:
ranganath_yadav, PAVAN86, Jaya_Kaja, rajani_vaddepalli15

July 17, 2008 06:41:48

jintojos

Member Since: May 2008 Contribution: 29

RE: sum of two numbers without using arithmetic operators

void main()
{
          int a=10,b=20;
          while(b--) a++;
           printf("Sum is :%d",a);
}

Is this answer useful? Yes | No

4 0

Overall Rating: +4

July 17, 2008 12:44:10

veeranarayana

Member Since: July 2008 Contribution: 1

RE: sum of two numbers without using arithmetic operators

int i,j;
if(i<j)
{
     for(i=0;i<=j;i++)
         j++;
    cout<<j;
}
else
{
   for(j=0;j<=i;j++)
       i++;
cout<<i;
}

Is this answer useful? Yes | No

1 0

Overall Rating: +1

July 18, 2008 12:22:08

ceren6

Member Since: July 2008 Contribution: 2

RE: sum of two numbers without using arithmetic operators

#include <stdio.h>

int main ()

{

unsigned int t = 0xffffffff;

unsigned int z = 1;

int a = 10, b = 10, sum = 0, r = 0;

while (t) {

int t1, t2;

t1 = a & 0x00000001;

t2 = b & 0x00000001;

if ((t1 ^ t2 ^ r) == 1) {

if (t1 == 1 && t2 == 1 && r == 1)

r = 1;

else

r = 0;

sum = sum | z;

} else {

if (t1 == 0 && t2 == 0 && r == 0)

r = 0;

else

r = 1;

}

a >>= 1;

b >>= 1;

z <<= 1;

t >>= 1;

}

printf ("sum: %dn", sum);

return 0;

}

Is this answer useful? Yes | No

July 21, 2008 05:48:29

ceren6

Member Since: July 2008 Contribution: 2

RE: sum of two numbers without using arithmetic operators

Operator Name	Syntax	Overloadable	Included in C
Arithmetic operators
Unary Plus	+a	Yes	Yes
Addition (Sum)	a + b	Yes	Yes
Prefix Increment	++a	Yes	Yes
Postfix Increment	a++	Yes	Yes
Assignment by Addition	a += b	Yes	Yes
Unary Minus (Negation)	-a	Yes	Yes
Subtraction (Difference)	a - b	Yes	Yes
Prefix Decrement	--a	Yes	Yes
Postfix Decrement	a--	Yes	Yes
Assignment by Subtraction	a -= b	Yes	Yes
Multiplication (Product)	a * b	Yes	Yes
Assignment by Multiplication	a *= b	Yes	Yes
Division (Quotient)	a / b	Yes	Yes
Assignment by Division	a /= b	Yes	Yes
Modulus (Remainder)	a % b	Yes	Yes
Assignment by Modulus	a %= b	Yes	Yes

Is this answer useful? Yes | No

1 0

Overall Rating: +1

August 14, 2008 13:18:18

Saurabh Sharma

Member Since: August 2008 Contribution: 1

RE: sum of two numbers without using arithmetic operators

Use minus operator :-
int a=10,b=20,c;
c=a-(-b);

Is this answer useful? Yes | No

August 22, 2008 01:50:32

sriranga.ch

Member Since: August 2008 Contribution: 4

RE: sum of two numbers without using arithmetic operators

void main()
{
int a=10,b=10;
a=a<<1;
b=b<<1;
printf("Sum of a&b is %dn",(a&b));
}

Is this answer useful? Yes | No

August 25, 2008 00:36:04

shiva chitta

Member Since: August 2008 Contribution: 2

RE: sum of two numbers without using arithmetic operators

#include add(int a,int b)
{
if(!a) return b;
else return add((a&b)<<1,a^b);
}
void main()
{ int a=2, b=5,c; c= add(a,b);
cout<<c;
}

hope it 'll help you right...........

Is this answer useful? Yes | No

September 09, 2008 15:45:00

rashmi.mohanty

Member Since: September 2008 Contribution: 8

RE: sum of two numbers without using arithmetic operators

void main(){
    int a=5,b=7,i;
    for(i=1;i<=a;i++)
         b++;
    printf("sum value:%d",b);
}

Is this answer useful? Yes | No

Go To Top