Sum of two numbers without using arithmetic operators

jintojos

 Profile Answers by jintojos 

• Jul 17th, 2008

 

void main()
 {
          int a=10,b=20;
          while(b--) a++;
           printf("Sum is :%d",a);  
 }

veeranarayana

 Profile Answers by veeranarayana 

• Jul 17th, 2008

 

int i,j;
if(i<j)
{
     for(i=0;i<=j;i++)
         j++;
    cout<<j;
}
else
{
   for(j=0;j<=i;j++)
       i++;
  cout<<i;
}

ceren6

 Profile Answers by ceren6 

• Jul 18th, 2008

 

#include
int main()
{
unsigned int t = 0xffffffff;
unsigned int z = 1;
int a = 10, b = 10, sum = 0, r = 0;
while (t) {
int t1, t2;
t1 = a & 0x00000001;
t2 = b & 0x00000001;
if ((t1 ^ t2 ^ r) == 1) {
if (t1 == 1 && t2 == 1 && r == 1)
r = 1;
else
r = 0;
sum = sum | z;
} else {
if (t1 == 0 && t2 == 0 && r == 0)
r = 0;
else
r = 1;
}
a >>= 1;
b >>= 1;
z <<= 1;
t >>= 1;
}
printf("sum: %dn", sum);
return 0;
}

ceren6

 Profile Answers by ceren6 

• Jul 21st, 2008

 

Arithmetic operators
Operator Name	Syntax	Overloadable	Included in C
Unary Plus	+a	Yes	Yes
Addition (Sum)	a + b	Yes	Yes
Prefix Increment	++a	Yes	Yes
Postfix Increment	a++	Yes	Yes
Assignment by Addition	a += b	Yes	Yes
Unary Minus (Negation)	-a	Yes	Yes
Subtraction (Difference)	a - b	Yes	Yes
Prefix Decrement	--a	Yes	Yes
Postfix Decrement	a--	Yes	Yes
Assignment by Subtraction	a -= b	Yes	Yes
Multiplication (Product)	a * b	Yes	Yes
Assignment by Multiplication	a *= b	Yes	Yes
Division (Quotient)	a / b	Yes	Yes
Assignment by Division	a /= b	Yes	Yes
Modulus (Remainder)	a % b	Yes	Yes
Assignment by Modulus	a %= b	Yes	Yes

Saurabh Sharma

 Profile Answers by Saurabh Sharma 

• Aug 14th, 2008

 

Use minus operator :-
int a=10,b=20,c;
c=a-(-b);

sriranga.ch

 Profile Answers by sriranga.ch 

• Aug 22nd, 2008

 

void main()
{
int a=10,b=10;
a=a<<1;
b=b<<1;
printf("Sum of a&b is %dn",(a&b));
}

shiva chitta

 Profile Answers by shiva chitta 

• Aug 25th, 2008

 

#include add(int a,int b)
{
 if(!a) return b;
else return add((a&b)<<1,a^b);
}
void main()
{ int a=2, b=5,c; c= add(a,b);
cout<<c;
}


hope it 'll help you right...........

rashmi.mohanty

 Profile Answers by rashmi.mohanty 

• Sep 9th, 2008

 

void main(){
    int a=5,b=7,i;
    for(i=1;i<=a;i++)
         b++;
    printf("sum value:%d",b);
}

npatwardhan

 Profile Answers by npatwardhan 

• Nov 2nd, 2008

 

Code
for (i = 0; i < a; i++) 


{


    count++;


}


for (j = 0; j < b; j++) 


{


    count++;


}


printf("%d", count);


 

sarav957

 Profile Answers by sarav957 

• Jul 10th, 2009

 

Code
#include<stdio.h>


int main()


{


    int i = 1, j = 20, c;


    c = (i ^ j);


    printf("%d", c);


    return 0;


}


 

ratnapaul

 Profile Answers by ratnapaul 

• Jul 18th, 2009

 

Code
main()<br />{<br />cout<<"Enter the numbers to be added";<br /> int a,b,x,y;<br /> cin>>a>>b;<br /> <br />do{<br /> x=a&b;<br /> y=a^b;<br /> x=a<<1;<br /> y=b;<br />}while(a);<br />cotu<<"The sum is:"<<y;<br />}

luckypavan

 Profile Answers by luckypavan 

• Oct 1st, 2010

 

Code
#include<stdio.h>


main()


{


    int a, b, c, d, sum;


    printf("n Please enter a,b values:");


    scanf("%d %d", &a, &b);


    if (b > a) {


        c = b - a;


    } else {


        c = a - b;              // using minus operator 


    }


    d = square(b) - square(a);  // using square function and - minus operator


    sum = d / c;                // using division operator


    printf("The sum of a and b is:%d", sum);


    return 0;


}

indravardhans

 Profile Answers by indravardhans 

• Jan 15th, 2011

 

Code
#include<stdio.h>


 


int result = 0X0;


int a, b, C = 0X0, aB, bB;


 


int main()


{


    int val = 0X1;


 


    scanf("%d%d", &a, &b);


    while (val) {


        aB = !!(a & val);


        bB = !!(b & val);


 


        if (aB ^ bB ^ C)


            result |= val;


 


        C = (aB & bB) | ((aB ^ bB) & C);


 


        val <<= 1;


    }


    printf("%d", result);


 


    return 0;


}

rome2all

 Profile Answers by rome2all 

• Aug 16th, 2011

 

Code
class Test {


    public static void main(String ... z) {


        System.out.println(4 || 8);     //use logical or symbol u can add it 


}}

sravan

• Aug 20th, 2011

 

Code
         #include<iostream.h>


         void main()


 {


      int i=20,j=30,m,n;


                         m=i,n=j;


if(i<j)


{


          for(i=1;i<=m;i++)


                        j++;


         cout<<j;


}


else


{


        for(j=1;j<=n;j++)


                 i++;


  cout<<i;


}


 }

mukesh kumar

• Mar 25th, 2012

 

Code
int main(){


int a,b;


printf("Enter the two numbers: 


");


 


scanf("%d",&a);


scanf("%d",&b);


printf("Sum is: %d",add(a,b));


} 

mahamad

• Jun 14th, 2012

 

Code
#include<stdio.h>


#include<conio.h>


main()


{


    int a=20,b=10,c;


    clrscr();


    c=a-~b-1;             //it will change the sign of operator truly magic


    printf("sum is %d",c);


    getch();


    return 0;


}

And

• Aug 28th, 2012

 

For two positive numbers:

int main(){
int a = 10;
int b = 10;

printf("%d",a ^ b | ((a & b)<< 1));
return 0;
}

mukesh

• Aug 10th, 2015

 

Simple

Code
 


void main()


{


int a=5,b=6,c;


c=a-(-b);


printf("%d",c)


 


}