A traveler walks a certain distance

A traveler walks a certain distance. Had he gone half a kilometer an hour faster , he would have walked it in 4/5 of the time, and had he gone half a Kilometer an hour slower, he would have walked 2 ½ hr longer. What is the distance?
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Akshujain

  • Oct 25th, 2009
 

d = 15 kms

x = speed in km/hr
y = time taken

d / x = y  - eq1
d / x + .5 = (4/5)*y - eq 2
d / x - .5 = 2.5 + y - eq 3
solving these three equation we get d = 15 x = 2 y = 7.5

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RAJUTHAI

  • Mar 8th, 2012
 

Ans:15km
solution:
speed(s)*time(t)=distance(d)
walked 1/2km with time 4/5
(s+0.5)((4/5)t)=d --->(1)
1/2km an hour slow, walked 2and half hr long
(s-0.5)(t+2.5)=d ----->(2)
solving (1) & (2)
we get s=2
t=7.5
d=2*7.5=15km

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