If a car starts from A towards B with some velocity due to some problem in the engine after traveling 30km.If the car goes with 4/5 th of its actual velocity the car reaches B 45min later to the actual time. If the car engine fails after traveling 45km, the car reaches the destination B 36min late to the actual time , what is the initial velocity of car and what is the distance between A and B in km

20 & 130

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sriii

  • Jul 4th, 2006
 

Can you give a clear explaination please.

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gaurav jagga

  • Apr 13th, 2007
 

distant between a&b is 135 km
vel. = 37.5km/hr

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Chul Min Kang

  • Oct 30th, 2007
 

Assume that Y is the distance from A to B and X is the velocity.

y/x + 3/4 = 30/x + (y-30)/(4x/5)    // '3/4' means 3/4 hour(45 min).
y/x + 3/5 = 45/x + (y-45)/(4x/5)    // '3/5' means 3/5 hour(36 min).

The answer is
x = 25(km/h), y = 105(km)

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