There are 45 members in a group. 9 members have shoes but no hats. 18 members have shoes. How many members are there who have only hats? a)12 b) 19 c) 27 d) 18

D)18.

no. of members who have both hats and shoes= 18 - 9 = 9

no. of members who have hats = 45 - 18 = 27

no. of members who have hats only hats = 27 - 9 = 18.

no of students have both shoes and hats is: 9 since 18 have shoe not mention about hat so (18-9) no of students have shoe alone is:9 from the total students 45, 45-(9+9)=27

Showing Answers 1 - 10 of 10 Answers

Neelam RAwat

Dec 1st, 2006

18 member have shoes(no mention of hats)

9 member have shoes but not hat

i.e the member who are havin only hats are 45-18=27

snehal

Dec 1st, 2006

d) 18

chandrakanth

Dec 17th, 2006

no. of members who have both hats and shoes= 18 - 9 = 9

no. of members who have hats = 45 - 18 = 27

no. of members who have hats only hats = 27 - 9 = 18.

dear.chandru12

Feb 20th, 2007

no of students have both shoes and hats is: 9 since 18 have shoe not mention about hat so (18-9) no of students have shoe alone is:9 from the total students 45, 45-(9+9)=27

varun sabharwal

Mar 3rd, 2007

since their are 9 members with shoes only and 9 others with hats and shoes so if we have to select one of the options we have to go with 27

Sandipan Dey

Mar 21st, 2007

As the question says find those who have only hats the answer is 27.... total students with shoes=18(among these 9 dont have hats) so no. of students with only hats=45-18=27

Eric9

Oct 26th, 2007

27

B-cause.

There is three groups.

1. Shoes and NO Hat

2. Shoes and Hat

3. No Shoes and Hat

<<If there is some members who doesn't hav anything,

the question hav to mention about that. BUT! There is no mention about that.

so, I can suppose that there is no member who doesn't hav anything. >>

use the venn diagrams formulae : A union B = A + B - A intersection B where AUB=45 (total) no.of people who've shoes A=18 no.of people who've hats B=? no.of people who've only shoes but not hats A-B = 9 no.of people who've shoes and hats A n B = 9 no.of people who've only hats but not shoes B-A = ? apply formula 45=18+B-9 => B=36 => B-A= 36-9 =27 Ans:c

## There are 45 members in a group. 9 members have shoes but no hats. 18 members have shoes. How many members are there who have only hats? a)12 b) 19 c) 27 d) 18

no. of members who have both hats and shoes=

18 - 9 = 9

no. of members who have hats = 45 - 18 = 27

no. of members who have hats only hats = 27 - 9 = 18.

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## Editorial / Best Answer

Answered by: dear.chandru12

no of students have both shoes and hats is: 9 since 18 have shoe not mention about hat so (18-9)

no of students have shoe alone is:9

from the total students 45, 45-(9+9)=27

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