Total Answers and Comments: 3
Last Update: October 18, 2006 Asked by: Arun Kumar
Submitted by : sultan Ans is d) 7th day
In d 1st day Anand does 1/7th of total work
similarly,
Bithu does 1/8th work in d 2nd day
hence at d end of 3 days, work done = 1/7+1/8+1/6=73/168
remaining work = (168-73)/168 = 95/168
again after 6 days of work, remaining work is = (95-73)/168 = 22/168
and hence Anand completes the work on 7th day.(hope u understood.)
Above answer was rated as good by the following members: piyush_dnma
July 25, 2006 10:11:13 #1
sultan
RE: Anand finishes a work in 7 days, Bittu finishes th... Ans is d) 7th day
In d 1st day Anand does 1/7th of total work
similarly,
Bithu does 1/8th work in d 2nd day
hence at d end of 3 days, work done = 1/7+1/8+1/6=73/168
remaining work = (168-73)/168 = 95/168
again after 6 days of work, remaining work is = (95-73)/168 = 22/168
and hence Anand completes the work on 7th day.(hope u understood.)
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September 22, 2006 06:12:56 #2
Vivek Shah
RE: Anand finishes a work in 7 days, Bittu finishes th... let thet speed of ship is =v
so seaplane speed must be=10v
let seaplane catch the ship in t time
so in t time ship moves x distance
so x/v=(x+18)/10v
x=2
so distance =18+2=20
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October 18, 2006 10:36:19 #3
parmeet singh
RE: Anand finishes a work in 7 days, Bittu finishes th... yarr it's not as difficult as it looks
see
the fastest guy takes 6 days if he is handeling alone ,but it is not hence option for 6 and 3 days is eleminated.
the slowest guy takes 8 days rest all are are fast so there is no way target will go over to 9 days
hence the only option is 7 days
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