RE: A work in 12 days b in 15 days. Find the no ...
ans 13 1/3 daysone day A work is x/12,one day B work is x/15,so we need alternate days x/12+x/15+........... =x(15x+12x)/(15*12)= 3x/20so for getting x we need to multiply 20/3that mean each A will work 20/3 day and B also work for 20/3 dayso 20/3+20/3=13 1/3 days
RE: A work in 12 days b in 15 days. Find the no ...
if we consider 2days of work work done by A in one day=(100/12)%work done by B in one day=(100/15)%Work done by A and B in 2 days=(100/12)+(100/15)=15%Obviously work done by A and B in 12 days=15% * 6 = 90%% of work left=10%case (1) if A initiates work, then A has to work on 13th day then work left =10 - (100/12)=1.66%On 14 th day B will work for=1.66*15/100=0.249Hence total no. of days=12+1+0.249=13.25=13 1/4 dayscase(2)if B initiates work, then B has to work on 13th day then work left =10 - (100/15)=3.33%On 14 th day A will work for=3.33*12/100=0.399Hence total no. of days=12+1+0.399=13.4=13 2/5 days
RE: A work in 12 days b in 15 days. Find the no ...
i donot really get the solution but i agree with venkatswami and arun ,because same work is done fastly by A than B.if A only works daily it will be 12 days as given but B who works slowly than A sahres the complete work in alternate days. so the answer will be definetly greater than 12 days.
