arvind

• Jun 29th, 2006

 

13 1/4 days

Default A starts the work

Salome

• Jul 1st, 2006

 

can u tell me how u got this ans?

shravan

• Jul 17th, 2006

 

answer will be 7 1/4 , it is as

   A+b in one day can work as 1/12+1/15=9/60

so in 6 days they work = 6* 9/60= 54/60

7th day has to be done by A , then = 54/60 + 1/12= 59/60

Remaining is =1-59/60= 1/60

on 8th day B has to do 1/60th of work, but he does 1/15 in one day, so in order to complete 1/60, he takes 1/4th of a day

so answer will be 7 + 1/4= 7 1/4 days

venkataswami

• Jul 27th, 2006

 

ans 13 1/3 daysone day A work is x/12,one day B work is x/15,so we need alternate days x/12+x/15+........... =x(15x+12x)/(15*12)= 3x/20so for getting x we need to multiply 20/3that mean each A will work 20/3 day and B also work for 20/3 dayso 20/3+20/3=13 1/3 days

venkataswami

• Jul 27th, 2006

 

13 1/3 is correct

venkataswami

• Jul 27th, 2006

 

13 1/4 (i checked is correct )

mohan N

• Aug 1st, 2006

 

i could not get you pls explain in easy way some body

Revathy

• Aug 10th, 2006

 

The answer to this question is 7 1/4 days. The explanation given by sharavan is correct

Arun

• Aug 28th, 2006

 

if we consider 2days of work work done by A in one day=(100/12)%work done by B in one day=(100/15)%Work done by A and B in 2 days=(100/12)+(100/15)=15%Obviously work done by A and B in 12 days=15% * 6 = 90%% of work left=10%case (1) if A initiates work, then A has to work on 13th day then work left =10 - (100/12)=1.66%On 14 th day B will work for=1.66*15/100=0.249Hence total no. of days=12+1+0.249=13.25=13 1/4 dayscase(2)if B initiates work, then B has to work on 13th day then work left =10 - (100/15)=3.33%On 14 th day A will work for=3.33*12/100=0.399Hence total no. of days=12+1+0.399=13.4=13 2/5 days

kriss

• Aug 30th, 2006

 

i donot really get the solution but i agree with venkatswami and arun ,because same work is done fastly by A than B.if A only works daily it will be 12 days as given but B who works slowly than A sahres the complete work in alternate days. so the answer will be definetly greater than 12 days.

paru

• Dec 5th, 2006

 

The correct ans is 13 1/4 days.The solution is shown below: A 's one day work = 1/12 B's one day work = 1/15 Since they are working alternately,two days work = 1/12+1/15 =9/60 Now, 4 days work = 9/60+9/60 = 2*(9/60) 6 days work = 3*(9/60) 8 days work = 4*(9/60) similarly,12 days work = 6*(9/60) = 54/60 On 13 th day A should work,so total work up to 13th day becomes 54/60+1/12=59/60 Remaining work = 1-59/60=1/60(Next day B should do the work as already mentioned that they work alternatively) As B's one day work is 1/15,he would take 1/ 4 th of the day to complete the 1/60 work. Total no. of days =13 1/4.

chaitanyawithu

 Profile Answers by chaitanyawithu Questions by chaitanyawithu

• Mar 26th, 2008

 

answer is 13 1/4days
lcm  of 12 and 15 is 60
ie total 60 units are to be manufactured
A makes 5units in a day(60/12)

B makes 4 units in a day(60/15)
now A starts the work
ie they make 54 items in 12days
then next 13th day A makes 5 units
remaining one unit made by B in 1/4 day
so ans is 12+1+1/4=13 1/4 days

abhikumar116

 Profile Answers by abhikumar116 

• May 13th, 2008

 

12 days

selvamkumar

 Profile 

• May 20th, 2008

 

ans34

m_manic

 Profile Answers by m_manic Questions by m_manic

• Dec 10th, 2009

 

In two day they can complete 3/20 of work. In 6 days they can complete 18/20 of work. 7 th day A complete the remaining work.
Total - 7days.