A,B,C r positive int.Out of them 2 r odd. Then 52a + ( b-5)3 (c-3)2 =

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Natarajan

  • Jul 5th, 2006
 

Ans is 52.

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shravan

  • Jul 17th, 2006
 

if we take a,b,c as 7,8,9 respectively, then answer will be something. if we take other values then its different, so answer cannot be determined.

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CHANDRA SEKHAR REDDY.MURE

  • Jul 25th, 2006
 

then i take a,b,c values are 2,,5,3then apply these values result is 104

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mpk

  • Jul 30th, 2006
 

even but cant be determine about the values.OK.

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VAIDHYA

  • Aug 9th, 2006
 

The answer is EVEN . There is no question of value .......... CHECK IT OUT

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mahesh

  • Sep 19th, 2011
 

i take odd numbers are 5,7
so the answer is152

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SOWJANYA

  • Sep 21st, 2011
 

52

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SOWJANYA

  • Sep 21st, 2011
 

52a+6(b-5)(c-3)
52a+6(bc-3b-5c+15)
52a-18b-30c+6bc+90

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SOWJANYA

  • Sep 21st, 2011
 

we cannot take values according to the A,B,C.'a,b,c' and 'A,B,C' .So we can simplify the given problem as 52a-18b-30c+6bc+90.We cannot specify value for this.

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