Const int perplexed = 2;#define perplexed 3main(){ #ifdef perplexed #undef perplexed #define perplexed 4 #endif printf("%d",perplexed);}

A) none of the above
B) 4
C) 2
D) 0
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bharath

  • Jul 16th, 2006
 

ans will be two not 4 as that value perplexed is const variable and a const can not be changed

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rts2006

  • Nov 11th, 2006
 

The answer is 4.

because The program is first preprocess to deal with macro, then the code become

const int perplexed = 2;
main()
{
printf("%d",4);
}

so, the result would be 4.

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