#define SQR(x) x * xmain(){ printf("%d", 225/SQR(15));}

A) 15
B) 225
C) 1
D) none of the above
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Rohit

  • Dec 14th, 2005
 

225

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mef526

  • Feb 13th, 2006
 

Use typical C coding guidelines and use

#define SQR(x) ((x) * (x))

And you get the desired answer: 1

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arjun

  • May 23rd, 2006
 

hi,in C, '*' has got higher precedence than '/', so the execution will be some what like this225/(15 * 15) hence the answer will be 1...;-)

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ramamaru

  • May 24th, 2006
 

Arjun u r wrong....Refer to michael's comment...

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yba

  • Jul 10th, 2007
 

In algebra * has higher precedence than /, but in C they have the same precedence, and are left-associative, meaning the operations are performed left to right.

So 225 / 15 * 15 gives (225/15)*15 or 225.

It is hard to say what intent is in this question, the intent is probably to trip you up.  Let us hope that is not the intent in real code, and that you use the form

#define SQR(x) ((x)*(x))

Because the next question might be what is the value of 225/SQR(3 * 5) ?

Inline functions are a lot safer than macros.

Sukumar Paul

  • Jul 24th, 2010
 

Yes the answer will be 225/15*15. As / and * has the same precedednce and associativity is from left to right so it will give 225(225/15*15 => 15*15 => 225).

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