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On a skating plane, Michel and Jennie are in a distance of a mile on each side of a point. They are going to skate to the direction of each other’s. Jennie, having added force with the flow of the wind, skated two and one-half miles faster than Michel and beat her 6 minutes. What are the times taken by both of them?

  
Total Answers and Comments: 2 Last Update: December 08, 2005     Asked by: sharad vasisht 
  
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December 02, 2005 04:54:10   #1  
Sea Bass        

RE: On a skating plane, Michel and Jennie are in a dis...
d rt where d is distance r is rate of speed and t is time.For both skaters distance 1 mile.Given:Jennie: 1 2.5r(t - 6)Michel: 1 rtFor Jennie's situation solving for rate:r d/t2.5r 1/(t - 6) // using substitutionr 1/2.5(t - 6) // divide by 2.5r 1/(2.5t - 15) // Jennie's rate (in miles/minute)Next substitute Jennie's rate for Michel's rate and solve for time:t d/rt 1/(1/(2.5t - 15)) // using substitutiont 2.5t - 15 // from here on out simplify equationt - 2.5t -15 -1.5t -15t 10 // Michel's time (in minutes)Jennie's time is t -6 therefore:Jennie took 4 minutes and Michel took 10 minutes.
 
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December 08, 2005 02:49:41   #2  
pallaviranib Member Since: December 2005   Contribution: 3    

RE: On a skating plane, Michel and Jennie are in a dis...
let michael speed r jennie 2.5r distance d 1mile r speed in miles/hrt time taken by michael in hrs so time taken by jennie t-(6/60) t-0.11 rt1 2.5r(t-0.1)solving these we get t 1/6hr 10min. so time taken by michael is 10 min and by jennie is 4min
 
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