Motorboat A leaves shore P as B leaves Q; they move across the lake at a constant speed. They meet first time 600 yards from P. Each returns from the opposite shore without halting, and they meet 200 yards from Q. How long is the lake?

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Abhijeet Hivarekar

  • Nov 21st, 2005
 

Distance between shores is 1000 yards

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PRI

  • Nov 23rd, 2005
 

1600 yards

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Guest

  • Dec 1st, 2005
 

P            600          AB    d-600                Q

P            d-200               BA          200      Q

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sharad vasisht

  • Dec 2nd, 2005
 

Plz tell the exact answer...whether its 1600,12,00 or 900.also with the approach..thanks

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vipin

  • Dec 28th, 2005
 

Correct answer is 1600 yard as first time they met 600 yard from p so the ratio of their speed at first time ll be 600:y-600(let y is total distance)for second meeting ratio ll be (y+200):2(y-100)equate both ratioes u ll get y=1600 yard

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Harry

  • Feb 1st, 2006
 

      

           ((x-600)+200)/600 = (600+(x+200))/x-600

           Solving this equation we get x = 1600.

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rakrak_2

  • Nov 2nd, 2006
 


                     600(A)                        x-600(B)
         p--------------------+----------------------------q

                          x-200(B)                           200(A) 
         p------------------------------------+------------q 


       600/(x-600)     =   ((x-600)+200) / 600+(x-200)
simplifying:

 600/(x-600)  = (x-400)/(x+400)

 600(x+400)=(x-600)(x-400)
 600x+240000  =x^2  -600x -400x + 240000
 x^2=1600x
 x=1600
so 1600 is the answer.

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