AbcD+abcd+aBCd+aBCD then the simplified function is (Capital letters are compliments of corresponding letters A=compliment of A. A. a B. ab C. abc D. a(bc)* E. (bc)*=compliment of bc

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veerabahu.m

  • Aug 4th, 2005
 

ans:B

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sambath_nataraj

  • Mar 21st, 2006
 

Answer is not 'a'

Solution:

abcD+abcd+aBCd+aBCD = abc(D+d) + aBC(d+D)

                                 = abc(1)+aBC(1)

                                 =abc+aBC

                                 =a(bc+BC)

This is not equal to a. b'coz, BC=The complement of (b+c) [DeMorgan' Law]

hussain

  • Apr 4th, 2006
 

good explanation

and try to check other questions

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NAGRA

  • Oct 14th, 2006
 

ans is abc+a(BC)*

by demorgan theorem

umamaheswari

  • Dec 6th, 2006
 

note:A is the complement of a

               abcD+abcd+aBcd+aBCD

              =a(bcD+bcd+BCd+BCD)

              =a(bc(D+d)+BC(d+D))(since D+d =1)

              =a(bc+BC)

              =a(1)

              =a

so ANS is: a(choice A)

    

Nilesh Patel

  • Apr 24th, 2007
 

A is not the correct ans..

bc+BC does not mean (1)

take B=1 And C=0 u will get (0)

der i think there might be some assumption base solution

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