A 12 address lines maps to the memory of A. 1k bytes B. 0.5k bytes C. 2k bytes D. none

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sahana.jain

  • Jul 22nd, 2005
 

it must be 4096=4k bytes.

sushma

  • Feb 23rd, 2006
 

the answer 4k is partially right...but answer is 4Kbits= 4096/8=512Bytes =0.5Kbytes

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