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 Aptitude  |  Question 14 of 26    Print  
2/3 of people read newspaper A , 3/4 read newspaper B. If 38 read both and 8 didn't
read any of the 2.how many read A?
48




  
Total Answers and Comments: 5 Last Update: December 22, 2006   
  
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October 25, 2005 14:28:36   #1  
Aaron C        

RE:
use the formulan(A) n(AuB)-n(B)+n(A intersection B)where n(AuB) total people-8
 
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October 25, 2005 14:30:46   #2  
Aaron C        

RE:
use the formulan(A) n(AuB)-n(B)+n(A intersection B)where n(AuB) total people-8
 
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March 23, 2006 11:18:50   #3  
pkaneria Member Since: March 2006   Contribution: 13    

RE: 2/3 of people read newspaper A , 3/4 read newspap...

Let us define A1 people who ready only A B1 people who read only B then we can say that A1+B1+38+8 A1+B1+46 T where T is the total number of people.

Now we also have A1+38 T*2/3 and B1+38 T*3/4.

Therefore we have A1 T*2/3-38 and B1 T*3/4-38

substituting in the first equal we get T*2/3 -38 + T*3/4 -38 +46 T

which leads to T 72

Therefore number of people who read A is 72*2/3 48.


 
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December 07, 2006 01:15:09   #4  
rems        

RE: 2/3 of people read newspaper A , 3/4 read newspap...

this answer is wrong dear!!!!

because T A1+B1+38+8 right???

u found A1 48 And B1 54(72*3/4)

then what wil be T?

48+54+38+8 ..........How this will be right?


 
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December 22, 2006 08:30:55   #5  
amarjeet kumar        

hi..........
if assume tot. x then(x-8) (2x/3)+(3x/4)-38 ...............thenx 72 anda 48
 
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