What is the value of the following series1/7 + 2/72 + 1/73 +2/74 + 1/75 + ……….

This question is related to Oracle Interview

Nathan Mirro

• Jul 26th, 2005

Following the pattern, the 1's and 2's repeat, and the other numbers increase...

2/74 + 1/75 + 2/76 + 1/77 + 2/78 + 1/79, etc.

• Jan 23rd, 2006

Use the harmonic progression

suman

• Nov 13th, 2006

Sana

• Aug 31st, 2007

1/7+1*[73^(-1) +.........................+(70+(2n+1))^-1+.......................]+2*[ 72^-1 + ........+(70+(2n))^-1+.................]

In the above series,the second term follows H.P with d=2 and a=73...reduce it using the sum of infinite terms in H.P----------------------------(1)

The third term also follows H.P with a= 72 and d=2..reduce it to the sum of infinite terms in H.P---------------------------(2)

use formula-> to simplify (1)  &  (2)

The above result will be the absolute answer!

• Dec 22nd, 2010

From the given equation the numbers are sequently incresed by one and decrease by 1 in numerator and in denominator it sequentialy increase by 1.

eg: 2/72+1/73+2/74

eg72,73,74,75.

so the next number is 76

and in numntr it incrs by 1