Nathan Mirro Jul 26th, 2005 Following the pattern, the 1's and 2's repeat, and the other numbers increase... - 2/74 + 1/75 + 2/76 + 1/77 + 2/78 + 1/79, etc.

Sana Aug 31st, 2007 1/7+1*[73^(-1) +.........................+(70+(2n+1))^-1+.......................]+2*[ 72^-1 + ........+(70+(2n))^-1+.................]In the above series,the second term follows H.P with d=2 and a=73...reduce it using the sum of infinite terms in H.P----------------------------(1)The third term also follows H.P with a= 72 and d=2..reduce it to the sum of infinite terms in H.P---------------------------(2)use formula-> to simplify (1) & (2)Now,add up (1),(2) and 1/7.The above result will be the absolute answer!

karthisiva Profile Answers by karthisiva Dec 22nd, 2010 From the given equation the numbers are sequently incresed by one and decrease by 1 in numerator and in denominator it sequentialy increase by 1.eg: 2/72+1/73+2/74eg72,73,74,75.so the next number is 76and in numntr it incrs by 1therefore the answer is 2/76+1/77+2/78...

## What is the value of the following series1/7 + 2/72 + 1/73 +2/74 + 1/75 + ……….

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