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A student is ranked 13th from right and 8th from left. How many students are there in totality ?

Asked by: Interview Candidate | Asked on: Aug 5th, 2005
Showing Answers 1 - 17 of 17 Answers
rajagopal

Answered On : Jun 15th, 2005

The answer is 20

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harry

Answered On : Jul 29th, 2005

It will be 20 students

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deepa

Answered On : Aug 5th, 2005

Ans is 20

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micsvikas

Answered On : Jan 7th, 2006

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20 Students

  
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Ajay Kumar

Answered On : Feb 7th, 2006

20 student

  
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prakhar saikia

Answered On : Apr 19th, 2006

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20

  
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13 and 8 is comman for both the side,12+7+1=20totality of the student is 20

  
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imran khan

Answered On : Jun 10th, 2006

Left=13-1=12right=8-1=7total=12+1+7=20

  
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Avdesh

Answered On : Oct 3rd, 2006

 Total  20 Students.

  
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Sagar Patel

Answered On : Sep 4th, 2007

Since there is student whose number is 13th from the right side and the same student has number 8th from the left, so in both the case the student is common.Hence the calculation should be like this:12+1=137+1=8since 1 is common in both the casehence,we add:12+7+1=20hence there are total 20 students standing in a cue.

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nick_2201

Answered On : Oct 22nd, 2007

It has to be 20, bcoz 1 is common in both side.

  
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rajat17111985

Answered On : Feb 1st, 2008

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Yes 20

  
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rajat17111985

Answered On : Feb 1st, 2008

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20 for sure

  
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Total no of student = (Rank form right + Rank from left)  - 1                           = (13 + 8) - 1                           = 20ans: 20                        

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bhushandolas

Answered On : Aug 31st, 2010

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There are 22 students.

  
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ashish.symbi

Answered On : Oct 20th, 2010

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There are 20 students.The sequence will be 7+1+12......=20 studentsThe 8th and 13th student is same.

  
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prititripathi

Answered On : Oct 23rd, 2010

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20 total student 13 from left including him n 7 frm left excluding him

  
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