Muthu

• Jun 2nd, 2005

 

$# will return the number of parameters that are passed as the command-line arguments.

Raj

• Jul 29th, 2005

 

$# means, number of positional parameters set

Max

• Jun 15th, 2006

 

Print $#This will return the last command is run successfully or not.If it will return 0 then it ran successfully. And if it will return other then 0 thenThere is some problem

Srinivas

• Aug 10th, 2006

 

I think it is $? not $# which returns the status of the last executed command

cmanne

 Profile Answers by cmanne 

• Mar 25th, 2007

 

$# returns the number of parameters that are passed to a shell script
$? returns the exit code of the last executed command (0 : Successful, 1 or other: Failed)

manu_khatri

 Profile Answers by manu_khatri 

• Feb 18th, 2011

 

By using $# parameter, the program checks whether the right number of arguments have been entered.

Mo

• Apr 20th, 2012

 

$# : Stands for counts of the number of the positional parameters passed to a script.

example test.sh 1 2 3 4 5 6 7 , there are 7 paramaters as passed so the count of the $# is 7