we have to pick pair of black and white
the combination is (BBW,BWB,WBB from socks rack)
chance for getting BBW: 18/34*17/33*16/32 = 9/66
chance of getting BWB = 18/34*16/33*17/32 = 9/66
chance o...

C. Table B gets created,but no rows gets inserted into Table A

Guest

Jan 4th, 2007

hian empty table table (B) will be created there is a mistake un the first statementno need to commit a Create instruction, so the rollback will have no effectgood luck

But when str[6]="string"; //6 characters
it printed string and not any absurd value....
then why only in case of str[7]="strings";//7 characters
it prints absurd value at the end???

(8/9)x*12/19=5/9,sollution multiply 8 with 9 and 9 with 5,so we get 72-45, and same for 12 and 19,we get 27x=108-95,x=13/27,x=1/2.1,largest number =9*1/2.1therfore the largest number is 4.5.

X:y=8:9 this means x is smaller than y(as x = (8/9)y). According to condition x+12/y-19 =5:99x+108 = 5y-95but 9x=8yso, 8y+108 = 5y-953y = -203y= -203/3, which is the larger number.

Miss, 90-45-45 is only for isosceles right angle triangle, there are other types of right angle triangles too. Suppose the sides are 3,4,5 as the sides are different the angles opp. to them will also be different.

anjali singh

Sep 15th, 2016

H^2=2pb
h^2=p^2 + b^2
p^2+ b^2=2pb
p^2 + b^2 -2pb=0
(p-b)^2=0
p-b=0
p=b
since both sides are equal
angle=45

All the answers mentioned above are true. This Question was posted long back at that point of time indexing was not possible in view. Now in SQL Server 2000 and Oracle latest versions its posible..

The answer is "e" because the value "abcdefgh" will get one index for each letter as:a=0b=1c=2d=3e=4f=5g=6h=7And since %c is written in question der4 only one letter will be our answer... and is "e" coz its index is 4.

Total stamps are the l.c.m of 3,4,5,6 i.e 60 and 1 is the remainder in all the cases.. so the toal stamp is 60+1=61 now deviding 61 with 8 leaves the remainder 5so if he want to make it a group of 8 he ll be having 5 stamps left