priya

• Aug 4th, 2005

 

The height is 20m

Anvar

• Dec 11th, 2005

 

Height is 4

visitor

• Jan 1st, 2006

 

First room cost equation : 4 X h X len X 0.1 = 60Second room cost equation : 4 X h X (len +5) X 0.1 = 80Solving the above , we get height = 10

Visitor

• Aug 29th, 2007

 

Why have you used 4 in ans : 4 * h * l * 0.1

Sana

• Aug 31st, 2007

 

A house will have four walls...
papers used only for construction of walls!!!!

1st House: 4 *a (side) *h (height) * 10 = 60   =======>     4ah=6 --(1)

Given 10 paise reqd...per construction of 1 square meters


2nd House: 4*(a+5) (side)*h (height) * 10 = 80 =======> 4ah + 20h=8---(2)

Area formula will be horizontal side*vertical height
the plane of wall will be along it's height!..

Solving (1) & (2) we get 20h=2.
Hence, h=0.1m

abhydaya

 Profile Answers by abhydaya 

• Jul 2nd, 2010

 

Let height of room 1 nd 2 be h1 nd h2
     we know h1=h2                                                        (given)
length of rooms be l1 nd l2
     also l2=l1+5                                                              (given)
area of 4 walls of 1st room a1=4*l1*h1
area of 4 walls of 2nd room a2=4*l2*h2
                                                 =4*(l1+5)*h1
cost for papering 1st room = a1*0.1 rs=4*l1*h1*0.1=rs 60                            ........1
cost for papering 2nd room = a2*0.1 rs=4*(l1+5)*h1*0.1=rs 80                   ........2
performing (eq1)/(eq2)

we get
         l1/(l1+5)=60/80
=>    l1=15m

substituting in eq1
       4*15*h1*0.1=60
=> h1=1/0.1
=>h1=10m

Ans:   h1=h2=10m

ips302

 Profile 

• Jul 5th, 2010

 

The height of both rooms are same.

skumar06cs

 Profile Answers by skumar06cs 

• Jul 22nd, 2010

 

4xh*10=60----1
4(x+5)h*10=80------2
After solving it we get 0.1m....

Thanks frnds..

z_12se

 Profile Answers by z_12se 

• Sep 3rd, 2010

 

10 m is the right answer. 10 paise=0.1 Rs