• #### we have two buckets, 1 of capacity 3liter and another of 5 liter.we have 5 liters of water.so how will we make combinations such that 1 bucket will have exactly 4 liters of water?

• Feb 28th, 2007

First pour 5 liter of water in 3 liter container .... now you will have 2 liter remaning in 5 liter...now empty the 3 liter and fill it with 2 liter from the 5 lit container..... now take 5 liter and pour one more liter to 3 liter container ...now you are left with 4 liter in 5 liter container
5   3
5    0
2    3
2    0
0    2
5    2
4    3

#### shivansh Mishra

• Oct 2nd, 2017

Fill 3 liters tank with water and pour into 5 liters tank than do it again the whole process. There will be 1 liters water in 3 liters tank. Now 5 liters tanks make it empty after that put the remaini...

#### Basavaraj

• Sep 11th, 2017

Step 1: Fill the 5 Ltr bucket. Step 2: Pour the 5 Ltr bucket to 3 Ltr bucket now 5 Ltr bucket has 2 Ltr of water. Step 3: Empty the 3 Ltr bucket and pour 2 Ltr remain from 5 Ltr bucket to 3 Ltr. No...

• #### Nvidia Placement Paper

there were 10 questions..4 X 3 marks***********1. room lighting.. room with 100 bulbs and switches..100 people goes in one by one.1st person toggles all switches2nd person toggles all switeches which r multiles of 2 ( 2,4,6..)and so on ( till 100th person toggling only 100th switch)once finished with all , which all bulbs r on..2. ieee single precision format for 1/5.form : 1 signbit, 8 bits for exponent,...

#### pshirishreddy

• Aug 18th, 2010

The answer is all the prime numbers from 1 - 100 the first person turns off all the lightsthe second person turns on the even lightsthe third person turns on the multiples of 3 turns off the even multiples of 3you can observe the sequence 2 3 5 7 .. following

#### kumar_sarma2000

• May 7th, 2007

to the bulbs question the answer is 10.the analysis is as follows;consider the factors of particular bulb excluding 1. first factor represents turning it OFF,second factor represents turning it ON,thi...

• #### CTS Aptitude Question paper

CTS Apti Question paper1. If all the 6 are replaced by 9, then the algebraic sum of all the numbers from 1 to 100(both inclusive) varies by Ans: 3302. The total no. of numbers that are divisible by 2 or 3 between 100 and 200(both inclusive) are Ans:673. From a pack of cards Jack, Queen, King & ace are removed. Then the algebraic sum of rest of the cards is Ans:2164. The average temperature of days...

#### jyothsna

• Jan 2nd, 2012

13th questions answer is 5. Step 1 : weigh 27,27 and 26 coins are left Step 2 : if one 27 measure less, weigh 9, 9 and 9 is left Step 3 : weigh 3, 3 and 3 is left Step 4 : weigh 1, 1 and 1 is left. ...

#### saurangsu

• Oct 1st, 2010

There is a simpler way of doing it.The numbers that are changed in two ways:i) 6 becomes 9, 16, becomes 19, 26 becomes 29....so on.... total 10 changes.Now for all the changes of the above mentioned t...