what will be the output class A { public static void main(String args[]) { System.out.println("Hi friend"); } } class Test { public static void main(String args[]) { System.out.println(" How are you"); } }

Manas Naik

• Jul 7th, 2012

When we compile it create two different class with name a.class and test.class .so,according to your call it will execute.
Example--java test
then output is "how are you" only not hi friend

Rashmi Ahuja

• Jun 16th, 2012

When we execute this class with class B then it first call to class A method main which is like normal method. after that B class print msg is printed

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ashish_setia  

 Profile Answers by ashish_setia Questions by ashish_setia

• Member Since Oct-2006 | Oct 3rd, 2006

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check out this example

class Checkmain{
public static void main(String args[]){
args[1]="ashish";
System.out.println("hello ");
}
}
class Checkmain1 extends Checkmain{
public static void main(String args[]){
System.out.println("how r u");
}

}
class Jo{
public static void main(String args[]){
String S[]=new String[10] ;

Checkmain.main(S);
Checkmain1.main(S);
}}

vivek

• Aug 26th, 2017

Yes you can only do that by overriding main method signature for eg main(String[] args) to main(). Certainly there are no other ways to do that because JVM needs strings array arguments to take comma...

Dharmendra Singh

• Sep 15th, 2016

yes we can"java public class HelloWorld { // arguments are passed using the text field below this editor public static void main(String[] args) { String []s =new Str...

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