printf("%d%d",f1(),f2());What is the sequence of function execution of the above statement. 1. printf, f1(), f2()2. printf, f2(), f1()3. f1(), f2(), printf4. f2(), f1(), printf.

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mohinuddinkhan  

 Profile Answers by mohinuddinkhan Questions by mohinuddinkhan

• Member Since Oct-2009 | Oct 30th, 2009

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Let's understand this by going through the following code

#include<stdio.h>
int f1();
int f2();

void main()
 {
 printf("%dt%d",f1(),f2());
}

int f1()
{
 printf("f1() enteredn");
 return 4;
}

int f2()
{
 printf("f2() enteredn");
 return 5;
}

O/P-

f2() entered
f1() entered
4        5

we can conclude f2() is 1st executed
then f1() and in the end printf().hence we can say the precedence of execution of functions are from right to left.

geek Jack

 Profile Answers by geek Jack Questions by geek Jack

• Aug 2nd, 2010

printf();then f2()then f1()then again printf()  to print the value in f1 f2 these are arguments to printf function.

omkar.lenka

 Profile Answers by omkar.lenka Questions by omkar.lenka

• Jul 29th, 2010

3)f1(),f2(),printf

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SURESH KUMAR KOLLIMALLA

• May 10th, 2013

By using dangling pointer we can access the values at the deallocated memory here, in the below code the memory allocated for variable n will be dealloeated as and when the control transfers from func...

ishwar

• Oct 19th, 2011

Dangling pointers arise when an object is deleted or deallocated, without modifying the value of the pointer, so that the pointer still points to the memory location of the deallocated memory.

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